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2 years ago

Toni and Jade live on the same street as the Middle School. Toni lives 6.1

Mathematics

1 answer:

Nataly_w [17]2 years ago

5 0

Answer:

Jade and Toni are 58.1 miles apart from each other.

Step-by-step explanation:

All you have to do is add the distances.

52 + 6.1 = 58.1

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It is 70 because common sense people

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2 years ago

How many solutions does this system have? 7. X = -2

Blizzard [7]

Answer:

One

Explanation:

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2 years ago

A standard sheet of paper in Europe is 21.0 cm wide and 29.7 cm long. Which has the greater area, the standard sheet of paper in

Tomtit [17]

Answer:

1 in = 2.54 cm

Part (a)

Answer: 8.268 in

Part (b)

Answer: 11.693 in

Part (c)

In SI units standard-sized paper is 21.0 cm by 29.7 cm, which is equivalent to 8.268 in by 11.693 in.

Answer: 8.268 in by 11.693 in.

Part (d)

U.S sized standard paper is 8.0 in by 11.0 in. Therefore the SI (internationally) sized paper is longer.

Part (e)

If the U.S> adopts the SI standard for letter-sized paper, both the width and length of standard paper will have to be increased. Therefore letter-sized paper will occupy a larger area and will be heavier if the thickness and density do not change.

Step-by-step explanation:

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2 years ago

Find the volume of a sphere made by rotating a circle with a radius of 12 inches. Use 3.14 for π and round to nearest whole numb

nydimaria [60]

Volume = 4/3×pi×r^3
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5 0

3 years ago

. An individual wishes to invest $5000 over the next year in two types of investment: Investment A yields 5%, and investment B y

tresset_1 [31]

Answer:

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

Step-by-step explanation:

Let

x -----> the amount invested at Investment A yields 5%

y -----> the amount invested at Investment B yields 8%

we know that

$x+y=5,000$

$x=5,000-y$ -----> equation A

$x \geq 0.25(5,000)$

$x \geq \$1,250$ -----> inequality B

$y \leq 0.50(5,000)$

$y \leq \$2,250$ -----> inequality C

$x \geq \frac{1}{2}y$ -----> inequality D

Substitute equation A in the inequality D and solve for y

$5,000-y \geq \frac{1}{2}y$

Multiply by 2 both sides

$10,000-2y \geq y$

Multiply by -1 both sides

$-10,000+2y \leq -y$

Adds y both sides

$-10,000+2y+y \leq 0$

$-10,000+3y \leq 0$

adds 10,000 both sides

$3y \leq 10,000$

Divide by 3 both sides

$y \leq \$3,333.33$ -----> inequality E

therefore

Solve for y

we have

$y \leq \$2,250$ -----> inequality C

$y \leq \$3,333.33$ -----> inequality E

The solution of inequality C and inequality E is

$y \leq \$2,250$

For y=2,250

x=5,000-y ----> x=5,000-2,250=2,750

$x \geq \$2,750$ -----> inequality F

Solve for x

we have

$x \geq \$1,250$ -----> inequality B

$x \geq \$2,750$ -----> inequality F

The solution of inequality B and inequality F is

$x \geq \$2,750$

therefore

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

7 0

2 years ago