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uranmaximum [27]

3 years ago

8

How do forces work In nature? (short answer please I'm lazy)

2 answers:

melisa1 [442]3 years ago

6 0

Answer:

Fundamental force, also called fundamental interaction, in physics, any of the four basic forces—gravitational, electromagnetic, strong, and weak—that govern how objects or particles interact and how certain particles decay. All the known forces of nature can be traced to these fundamental forces

Explanation:

Alekssandra [29.7K]3 years ago

4 0

<em>Long Answer </em>: <em>The strong force is that force which cause the basic pieces of an atom to hold together. The weak force is radiation; this force is instrumental in things decaying. Electro-magnetism is the charged field which surrounds iron based materials or objects.</em>

Short answer: <em><u>Gravity</u></em>

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Mars2501 [29]

Answer:

Therefore % increase in velocity is 18.23 %

Explanation:

we use the equality of mass flow rate and the areas

$m_1 = m_2\\p_1v_1 = p_2v_2\\p_1A_1v_1 = p_2A_2v_2\\v_2 = \frac{p_1}{p_2} v_1$

The percentage increase in velocity is

Δ v% = $\frac{v_2 - v_1}{v_1} \\$ 100%

= $\frac{p_1}{p_2} v_1 - v_1$ .100%

= $\frac{\frac{1.2}{1.015} - 1}{1}$ . 100%

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3 years ago

An airplane flying parallel to the ground undergoes two consecutive displacements. The first is 50 km 60.0° west of north, and t

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2 years ago

A load of 800 N is lifted using a block and tackle having 5 pulleys. If the applied effort is 200 N, calculate

ser-zykov [4K]

Explanation:

Load=800N

Effort=200N

1. Mechanical Advantage = LOAD/EFFORT

= 800N/200N

= 4

2 Velocity Ratio = no. Of pulleys =5

3. Efficiency = Mechanical advantage / velocity ratio × 100%

= (4/5)×100%

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4. output work= load×load distance

= 800N × 5m

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5. Efficiency = (output work/input work) ×100%

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I hope it helped! ;-)

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3 years ago

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A bicycle racer inflates their tires to 7.1 atm on a warm autumn afternoon when temperatures reached 27 °C. By morning the tempe

natulia [17]

Answer:

The required pressure is 6.4866 atm.

Explanation:

The given data : -

In the afternoon.

Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa

Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K

In the morning .

Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K

Given that volume remains constant.

To find final pressure ( p₂ ).

Applying the ideal gas equation.

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$\frac{p}{T} = constant$

$\frac{p_{1} }{T_{1} } = \frac{p_{2} }{T_{2} }$

$p_{2} = \frac{T_{2} }{T_{1} } *p_{1}$

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8 0

3 years ago