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astraxan [27]
3 years ago
14

What is the period of a 4.12 m long pendulum?

Physics
1 answer:
lisov135 [29]3 years ago
8 0
Using the equation for period length, you get an answer of about 4.1 seconds.
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The density of gold is 19.3 g cm³. What is the mass of a bar of gold in Kg that measures 6 cm x 4 cmx to 2 cm ?
klemol [59]

Answer: 0.9264 kg

Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.

The volume is 6cm*4cm*2cm = 48 cm^3 (cc).

Density of Au is 19.3 g/cc

Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au

1 kg = 1,000 g

(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs

At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).

3 0
3 years ago
The atomic number of a nucleus decreases during which nuclear reactions?
Goryan [66]
A related type of beta decay actually decreases the atomic number of the nucleus when a proton becomes a neutron. Due to charge conservation, this type of beta decay involves the release of a charged particle called a “positron” that looks and acts like an electron but has a positive charge.
5 0
3 years ago
Using the law of conservation of angular momentum, estimate how fast a collapsed stellar core would spin if its initial spin rat
Nataly_w [17]

Answer:

\omega_{f} = 1000000\,\frac{rev}{day}

Explanation:

The law of conservation of angular momentum states that angular momentum remains constant when there is no external moment or forces applied to the system. Let assume that star can be modelled as an sphere, then:

\frac{2}{5}\cdot M\cdot R_{o}^{2} \cdot \omega_{o} = \frac{2}{5}\cdot M\cdot R_{f}^{2} \cdot \omega_{f}

The final angular speed is:

\omega_{f} = \omega_{o}\cdot (\frac{R_{o}}{R_{f}})^{2}

\omega_{f} = (1\,\frac{rev}{day} )\cdot (\frac{10000\,km}{10\,km} )^{2}

\omega_{f} = 1000000\,\frac{rev}{day}

3 0
3 years ago
Which of the following organisms are known as producers?
timofeeve [1]

Answer:

A,B.D

Explanation:

4 0
3 years ago
Read 2 more answers
In a certain oscillating LC circuit, the total energy is converted from electrical energy in the capacitor to magnetic energy in
aleksandrvk [35]

Answer:

A = 5.6μs

B = 178.57kHz

C = 2.8μs

Explanation:

A. It takes ¼ of the period of the circuit before the total energy is converted from electrical energy in the capacitor to magnetic energy in the inductor.

t = T/4

T = 4*t

T = 4 * 1.4 = 5.6μs

B. f = 1/T

Frequency is the inverse of period

f = 1 / 5.6*10⁻⁶

f = 178571.4286Hz

f = 178.57kHz

C. time taken for maximum energy to occur is T/2

t = 5.6 / 2 = 2.8μs

5 0
3 years ago
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