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3 years ago

What is the period of a 4.12 m long pendulum?

Physics

1 answer:

lisov135 [29]3 years ago

8 0

Using the equation for period length, you get an answer of about 4.1 seconds.

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Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface. When she lands on Noveria, a distant planet in

Anastasy [175]

Answer:

Acceleration of gravity on Noveria = 4.4 m/s²

Explanation:

Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface.

We have weight, W = mg

Acceleration due to gravity, g = 9.81m/s²

799 = m x 9.81

Mass of Shepard, m = 81.45 kg

She lands on Noveria, a distant planet in our galaxy, she weighs 356 N.

We have weight, W = mg'

356 = 81.45 xg'

Acceleration of gravity on Noveria, g' = 4.4 m/s²

6 0

4 years ago

Two rocks weighing 5 Newtons and 10 Newtons are dropped simultaneously from the same height onto a Coyote. After three seconds o

Ilia_Sergeevich [38]

<h2>Potential energy lost by 10 N rock will be greater</h2>

Explanation:

Two rocks of 5N and 10N falls from the same height . Thus they will loose the potential energy.

The potential energy lost = mass x acceleration due to gravity x height

The potential energy lost by first 5 N rock = 5 h

Because weight of rock m g = 5 N

Similarly , the potential energy lost by 10 N Rock = 10 h

here weight of rock m g = 10 N

Thus comparing these two , the potential energy lost by 10 N rock is greater than that of 5 N rock .

5 0

4 years ago

A radio station broadcasts at a frequency of 600 kHz. Knowing that radio waves have a speed of 300 000 000 m/s, what is the wave

soldier1979 [14.2K]

Answer:

ccvtesgdujtdchgdrgggggggfrrrtyfaasdddfffghgdshh

6 0

3 years ago

Kepler's 3rd law: harmonic law

Amanda [17]

<span>orbital velocities to their mean distances from the Sun.</span>

7 0

3 years ago

Kim throws a beach ball up in the air. It reaches its maximum height 0.50s later. We can ignore air resistance. What was the bea

notka56 [123]

Answer:

The beach ball's velocity at the moment it was tossed into the air is <u>4.9 m/s.</u>

Explanation:

Given:

Time taken by the ball to reach maximum height is, $t=0.50\ s$

We know that, velocity of an object at the highest point is always zero. So, final velocity of the ball is, $v=0\ m/s$

Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is, $a=g=-9.8\ m/s^2$

The negative sign is used as acceleration is a vector and it acts in the downward direction.

Now, we have the equation of motion relating initial velocity, final velocity, acceleration and time given as:

$v=u+at$

Where, 'u' is the initial velocity.

Plug in the given values and solve for 'u'. This gives,

$0=u-9.8(0.5)\\u=9.8\times 0.5\\u=4.9\ m/s$

Therefore, the beach ball's velocity at the moment it was tossed into the air is 4.9 m/s

3 0

3 years ago

Read 2 more answers