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3 years ago

What is an electromagnetic wave?

Physics

1 answer:

Sphinxa [80]3 years ago

6 0

Answer:

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field.

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All of the halogens are____to humans.

Ymorist [56]

Answer:

b bc they are a dangerous threat to humans health

5 0

1 year ago

a typical top fuel dragstar has a mass of 900 kg what is the force applied to a dragstar by the static friction of the strip the

AnnZ [28]

Wonderful.
You've given us ' m '.
Now, if we only had ' a ', we could come back at you with ' f '.

6 0

4 years ago

To drive a typical car at 40 mph on a level road for one hour requires about 3.2 × 107 J of energy. Suppose we tried to store th

tatiyna

Answer:

9000RPM

Explanation:

"Angular velocity" is directly related to kinetic energy, that is, the Kinetic energy equation would allow an approximation to the resolution investigated in the problem.

The equation for KE is given by:

$KE = \frac{1}{2} lw ^ 2$

Now, starting from there towards the <em>Angular equation of kinetic energy</em>, the moment of inertia (i) is used instead of mass (m), and angular velocity (w) instead of linear velocity (V)

That's how we get

$KE_{Angular} = \frac{1}{2} Iw^2$

calculating the inertia for a solid cylindrical disk, of

m = 400kg

r = 1.2 / 2 = 0.6m

$I_{disk} = \frac{1}{2} mr^2 = (0.5) (400) (0.6)^2 = 72 kgm^2$

We understand that the total kinetic energy is 3.2 * 10 ^ 7J, like this:

$3.2*10^7 = \frac{1}{2} Iw^2 = (0.5) (72) w^2 = 36w^2$ $w^2 = 3.2*10^7 / 36 = 0.0888*10^7 = 88.8*10^4$

$w = 9.43*10^2 = 943 rad / s$

Thus,

943 rad / s ≈ 9000 rpm

6 0

3 years ago

State two reasons why the rod is not in equilibrium

Lubov Fominskaja [6]

Answer:

For equilibrium the net torque on the rod must be zero. So the 100N forces should on either side of the pivot point i.e. one on the left and one the right, and in same direction.

5 0

3 years ago

A racquet ball with mass m = 0.238 kg is moving toward the wall at v = 12.4 m/s and at an angle of θ = 31° with respect to the h

Mamont248 [21]

Answer:

$||\vec p || = 2.951\,\frac{kg\cdot m}{s}$

Explanation:

The initial momentum of the racquet ball is:

$||\vec p || = (0.238\,kg)\cdot (12.4\,\frac{m}{s} )$

$||\vec p || = 2.951\,\frac{kg\cdot m}{s}$

5 0

3 years ago