Answer:
94.8454
Explanation:
Let volume be V
Let Temperature be T
V1= 92
T1= 3C but to kelvin 273+3= 300K
V2= ?
T2= 18 C but to kelvin 18+273= 291





Answer : The molar heat of fusion for substance X is, 775.6 cal/mol
Explanation :
First we have to calculate the moles of substance X.

Given:
Molar mass of substance X = 58.45 g/mole
Mass of substance X = 326.0 g
Now put all the given values in the above expression, we get:

Now we have to calculate the molar heat of fusion for substance X.

where,
Q = heat releases = 4325.8 cal
= molar heat of fusion for substance X = ?
n = moles = 5.577 mol
Now put all the given values in the above expression, we get:

Thus, the molar heat of fusion for substance X is, 775.6 cal/mol
In order to balance reactions, the number of each element must be the same on the left and right side. If I have 3 of element X on one side, I must have 3 of element X on the other side. That being said:
Zn + Fe(NO3)2 —> ZnNO3 + Fe
I have two NO3 groups on the left, so I will add a coefficient of 2 in front of the compound which has an NO3 group on the right side.
Zn + Fe(NO3)2 —> 2ZnNO3 + Fe
Since I now have 2 Zn’s on the right, and only 1 on the left, I will add a coefficient of 2 in front of Zn on the left.
2Zn + Fe(NO3)2 —> 2ZnNO3 + Fe
Lets check:
Zn: 2 right, 2 left (correct)
Fe: 1 right, 1 left (correct)
NO3 groups: 2 right, 2 left
We have successfully balanced the equation. :)
Answer:
The answer will have to be A