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jeka94
2 years ago
8

When baking cookies, what is one chemical change that takes place?

Chemistry
2 answers:
Gelneren [198K]2 years ago
7 0

Answer:

C. forming cookies into balls

Alexus [3.1K]2 years ago
6 0

Answer:

A. chocolate chips melting

Explanation:

It is a chemical change. cookies will soften and melt slightly as the cookies bake. the change is solid to liquid.

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identify the reagents necessary to achieve each of the following transformations o3 dms, pcc, ch2cl, h2so4,h2o,hgso4
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the reagents necessary to convert alcohol to ketoneNa_2Cr_2O_7 , H_2O which involves oxidation of alcohols.

<h3>What is oxidation of alcohols?</h3>
  • Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
  • In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
  • In order to cause primary alcohols to oxidize into aldehydes
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  2. CrO_3/pyridine (Collins reagent)
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  • oxidation of secondary alcohols to ketones
  1. Cr_2O_7 ^-^2 (dichromate)
  2. CrO_3/pyridine (Collins reagent)
  3. Chromium pyridinium compound (PCC)
  4. Dichromate of pyridinium (PDC, Cornforth reagent)
  5. Periodinane by Dess-Martin
  6. Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
  7. CrO_3, H_2SO_4/acetone (Jones oxidation)
  8. Acetone with aluminum isopropoxide (Oppenauer oxidation)

To learn more about oxidation of alcohols with the given link

brainly.com/question/7207863

#SPJ4

<u>Question:</u>

Identify the reagents necessary to achieve each of the following transformations

a. O_3 , DMS

b.H_2SO_4 , H_2O , HgSO_4

c.Na_2Cr_2O_7 , H_2O

d.Fe ^ {2+}, NaOH

3 0
2 years ago
If 7.4 moles of carbon dioxide is produced in this reaction, how many moles of oxygen gas would be needed?
Nimfa-mama [501]

Answer:

11.6 mol O₂

Explanation:

  • C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂O

In order to solve this problem we need to <u>convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂)</u>. To do so we'll use a conversion factor containing the <em>stoichiometric coefficients</em> of the balanced reaction:

  • 7.4 mol CO₂ * \frac{11molO_2}{7molCO_2} = 11.6 mol O₂
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this is the answer

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