Answer:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
Answer:
x=1
Step-by-step explanation:
5x=5x x=1
14: 1 × 14
2 × 7
56: 1 × 56
2 × 28
4 × 14
7 × 8
63: 1 × 63
3 × 21
7 × 9
GCF(14, 56, 63) = 7
No, it would leave a decimal
Answer:
The 2nd table.
Step-by-step explanation:
It is the only one that makes sense.
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