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Anika [276]
3 years ago
11

I just need b isolatedwill mark brainliest

Physics
2 answers:
BigorU [14]3 years ago
7 0

Answer:

b=\frac{2d}{t}-a

Explanation:

\frac{(a+b)}{2}t=d\\\\2(\frac{(a+b)}{2}t)=d(2)\\\\t(a+b)=2d\\\\\frac{t(a+b)}{t}=\frac{2d}{t}\\\\a+b=\frac{2d}{t}\\\\a+b-a=\frac{2d}{t}-a\\\\b=\frac{2d}{t}-a

adoni [48]3 years ago
4 0
To solve for B, divide each side by T and multiply by 2, do dt/2 then subtract a
The final answer is b=(dt/2)-a
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Give 5 real life examples of a tension​
Delvig [45]

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6 0
2 years ago
For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin
Art [367]

Answer:

width of slit(a)≅ 0.1mm

Explanation:

Wave length of laser pointer =λ = 685 nm

Distance between screen and slit = L = 5.5 m

Width of bright band = W=8.0cm=0.08m

width of slit=a

recall the formula;

W=(2λL)/a

a=2λL/W

a=(2 *685*10⁻⁹*5.5m)/0.08m

a=7535*10⁻⁹/0.08

a=94187.5 *10⁻⁹

a=0.0000941875m

a=0.0941875mm

a≅0.1mm

5 0
3 years ago
Read 2 more answers
What is 6.02 x 10^4 in standard notation
Vesnalui [34]
I believe you mean 6.02*10^7 but you want to shift the decimal 7 times to the right which would be 60200000 (:
4 0
3 years ago
An airplane is flying through a thundercloud at a height of 2000 m (This is a very dangerous thing to do because of updrafts, tu
Doss [256]

Answer:

400000\ \text{N/C}

Explanation:

q_1 = Charge at 3000 m = 40 C

q_2 = Charge at 1000 m = -40 C

r_1 = 3000 m

r_2 = 1000 m

k = Coulomb constant = 9\times10^9\ \text{Nm}^2/\text{C}^2

Electric field due to the charge at 3000 m

E_1=\dfrac{k|q_1|}{r_1^2}\\\Rightarrow E_1=\dfrac{9\times 10^9\times 40}{3000^2}\\\Rightarrow E_1=40000\ \text{N/C}

Electric field due to the charge at 1000 m

E_2=\dfrac{k|q_2|}{r_2^2}\\\Rightarrow E_2=\dfrac{9\times 10^9\times 40}{1000^2}\\\Rightarrow E_2=360000\ \text{N/C}

Electric field at the aircraft is E_1+E_2=40000+360000=400000\ \text{N/C}.

7 0
3 years ago
A light beam is directed parallel to the axis of a hollow cylindrical tube. When the tube contains only air, the light takes 8.7
monitta

Answer:

Explanation:

velocity of light in a medium of refractive index V = V₀ / μ

V₀  is velocity of light in air and μ is refractive index of light.

time to travel in tube with air =  length of tube / velocity of light

8.72 ns = L / V₀  L is length of tube .

time to travel in tube with jelly =  length of tube / velocity of light

8.72+ 1.82  = L / V  L is length of tube .

10.54 ns = L / V

dividing the equations

10.54 / 8.72 = V₀  / V

10.54 / 8.72 =   μ

1.21 =  μ

refractive index of jelly = 1.21 .

3 0
3 years ago
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