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Lemur [1.5K]
3 years ago
10

On occasion, it has been found that the oxidation of borneol doesn't go to completion (possibly because of poor stirring or insu

fficient Oxone). This reaction would probably be easy to monitor via TLC, however. Which component should have a lower Rf, and why
Chemistry
1 answer:
seraphim [82]3 years ago
3 0

Answer:

Check the explanation

Explanation:

Here, Nitrogen (N) undergoes oxidation and Chlorine (Cl) undergoes reduction.

To answer your question:

N is oxidized from an oxidation number of -3 to an oxidation number of -1.

Cl is reduced from oxidation number of +1 to an oxidation number of -1.

Now,

Borneol should have a lower Rf because of boiling point.

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<u>Answer:</u> The theoretical yield of acetanilide is 6.5 grams.

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Putting values in above equation:

1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g

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Putting values in equation 1, we get:

\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol

The chemical equation for the reaction of aniline and acetic anhydride follows:

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So, 0.048 moles of aniline will react with = \frac{1}{1}\times 0.048=0.048mol of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

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Putting values in equation 1, we get:

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Hence, the theoretical yield of acetanilide is 6.5 grams.

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