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trapecia [35]
3 years ago
15

Solve 9x + 3y= 15 for y.A. y= -3x+5B. y= -3x+15C. y= 9x+15D. y= -9x+5​

Mathematics
2 answers:
Elenna [48]3 years ago
5 0

Answer:

y= -3x+5

Step-by-step explanation:

To solve for y, you need to get y by itself on the left side.

Subtract 9x from both sides to get 3y= -9x+15.

Then, divide 3 from both sides to get y= -3x+5.

Hope this helps!

Nadya [2.5K]3 years ago
4 0

Answer:

A

Step-by-step explanation:

I got y = 5 - 3x which is the same as y = -3 + 5

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An arithmetic sequence is a sequence that adds or subtracts the same amount every time, making the answer C. The numbers are increasing by +5 consistently.

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4 0
3 years ago
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an item is regularly sold at $40. kala bought it at a discount of 35% off the regular price. how much did kala pay
KonstantinChe [14]

To solve this problem, we must first find the discount amount, and then subtract this amount from the total price of the item.

To find the discount amount, we must find 35% of $40. To do this, we must first convert 35% to its decimal equivalent by dividing 35/100. We do this because percentages are parts out of a total 100 percent, thus this fraction represents an equivalent value that we can multiply by other numbers. Using our knowledge that 35/100 = 0.35, we can now set up our expression:

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To solve, we just multiply these two numbers together, which gives us 14.

This means that Kala got a discount of $14 off of the original price of $40. To find out how much she paid for it, we must subtract $14 from $40, as modeled below:

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5 0
4 years ago
Solve the system by graphing.<br><br> 3x+8y=16<br><br> 3x+8y=-64
Gnesinka [82]

<em>-3x-y=10</em>

<em>4x-4y=8</em>

<em>or</em>

<em>y = -3x - 10 </em>

<em>P(0,-10) and P(-2, -4) on this line: Plot and connect with the Line.</em>

<em></em>

<em> </em>

<em>y = x - 2</em>

<em>P(0, -2) and (2,0) on this line: Plot and connect with the Line.</em>

<em>P(-2,-4) is the ordered pair that is the solution for this system of EQs</em>

<em>On may CHECK by substituting x= -2 and y = -4 into the EQs of these Lines</em>

<em></em>

<em>Hope this helps!!!</em>

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