Answer:
Places where primary succession occurs include newly exposed rock areas, sand dunes, and lava flows. Simple species that can tolerate the often- harsh environment become established first. These organisms help enrich the soil, allowing other species to become established.
Image result for think about succession and the places you have seen or visited. choose one place, provide evidence from your experience, to determine whether your example showed primary or secondary succession. you can write and/or include pictures
For example, after a forest fire that kills all the mature trees on a particular landscape, grasses might grow, followed by shrubs and a variety of tree species, until eventually the community that existed before the fire is present again
Answer:
9 atoms
Explanation:
Explanation: In 1 formula unit of Al(NO3)3 , there are (clearly!) 9 atoms of oxygen, 3 nitrogen atoms, and 1 aluminum atom. I have gone on before that the mole ( NA , Avogadro's number) is simply a much larger number, i.e. NA = 6.022×1023 .
Every single bond is a sigma bond.
A double bond contains 1 sigma bond and 1 pi bond.
A triple bond contains 1 sigma bond and 2 pi bonds.
For example, in acetylene, H-C≡C-H, the sigma bond is formed by the head-on overlap of two sp orbitals. The pi bonds are formed by the side-on overlap of 2p orbitals.
The correct answer is
D burning wood
because it's changing the wood.
The other's are physical changes because it's still the same thing, it's just in a different form.
Glad I could help, and good luck!
AnonymousGiantsFan
Answer:
Oxidation state] is defined as the charge an atom might be imagined to have when electrons are counted according to an agreed-upon set of rules:
The oxidation state of a free element (uncombined element) is zero for a simple (monoatomic) ion, the oxidation state is equal to the net charge on the ion.
Hydrogen has an oxidation state of 1 and oxygen has an oxidation state of −2 when they are present in most compounds. (Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g. H2O2 the algebraic sum of oxidation states of all atoms in a neutral molecule must be zero, while in ions the algebraic sum of the oxidation states of the constituent atoms must be equal to the charge on the ion.
The same is written in my textbook. But how am I supposed to find the ox. number of an atom, which is in compound like K2UO4?
