A car travels 65 miles in 1 hour. What is the average speed of the car?

What is the definition of periodic trend

Black_prince [1.1K]

Answer:

That periodic trends are specific patterns that are present in the periodic table that illustrate different aspects of a certain element, including its size and its electronic properties.

Explanation:

4 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION THIS FREAKING SUCKS

tigry1 [53]

Answer:

m = 0.122 m

Explanation:

Molality(m): A measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

$\mathrm{Molality\:Formula}:\quad \mathrm m = \dfrac{ mole\:of\:solute }{ mass\:of\:solvent\:in\:kg }$

$\mathrm m = \dfrac{ mole}{ kg }$

$\mathrm{Substitute\:the\:numbers\:into\:the\:"Molality\:Formula"}$

$\mathrm m = \dfrac{ 0.250 }{ 2.05 }$

$\mathrm{Divide\:0.250\:by\:2.05\:and\:get\:0.12195122}$

$\mathrm m = {0.12195122}$

$\mathrm{Round\:to\:the\:nearest\:thousandths\:place}$

$\mathrm m = 0.122$

8 0

3 years ago

The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.

Vikki [24]

Answer : The solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

Solution : Given,

$K_{sp}=2.42\times 10^{-11}$

Molar mass of $MnCO_3$ = 114.945g/mole

The balanced equilibrium reaction is,

$MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3$

At equilibrium s s

The expression for solubility constant is,

$K_{sp}=[Mn^{2+}][CO^{2-}_3]$

Now put the given values in this expression, we get

$2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L$

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

$s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L$

Therefore, the solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

8 0

3 years ago

Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca

lina2011 [118]

<u>Answer:</u> The above reaction is non-spontaneous.

<u>Explanation:</u>

For the given chemical reaction:

$Ni^{2+}(aq.)+2Fe^{2+}(aq.)\rightarrow 2Fe^{3+}(aq.)+Ni(s)$

Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

$E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=-0.23-0.77=-1.0V$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

Hence, the above reaction is non-spontaneous.

3 0

3 years ago

What are the missing coefficients for the skeleton equation below? Cr(s) + Fe(NO3)2(aq) → Fe(s) + Cr(NO3)3(aq)

postnew [5]

Answer:

2 3 3 2

Explanation:

7 0

3 years ago

A car travels 65 miles in 1 hour. What is the average speed of the car?​

A car travels 65 miles in 1 hour. What is the average speed of the car?