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AnnyKZ [126]
3 years ago
13

An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train . When the engineer first

sees the car, the locomotive is 110 m from the crossing and its speed is 21 m/s . If the engineer's reaction time is 0.6 s, what should be the magnitude of the minimum de celeration to avoid an accident ? Answer in units of m/s^ 2
Physics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer:

Explanation:

distance traveled during reaction time

d = vt = 21(0.6) = 12.6 m

distance remaining 110 - 12.6 = 97.4 m

Assuming we want zero speed in 97.4 m using constant acceleration.

a = (0² - 21²) / 2(97.4) = - 2.2638603...

the negative value indicates acceleration opposes initial velocity.

magnitude is

a = 2.3 m/s²

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b) On the Moon

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c) On Mars

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d)in outer space traveling with constant velocity.

0

Explanation:

The weight is defined as:

W = mg (1)

Where m is the mass and g is the gravity

a) On Earth g = 9.8m/s^{2}

Then, equation 1 can be used:

W = (50Kg)(9.8m/s^{2})

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but 1N = Kg.m/s^{2}

W = 490N

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Hence, the weight of the astronaut on the Moon is 85N

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Tanking into consideration that the astronaut is traveling in outer space at a constant velocity, it can be concluded that the acceleration will be zero.

Remember that the acceleration is defined as:

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W = (50kg)(0)

Remember that g is the acceleration that a body experience as a consequence of the gravitational field.

 

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