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defon
4 years ago
8

How does adding more of a substance affect it's density?

Physics
2 answers:
fomenos4 years ago
5 0
I’m going to use molasses as an example of a substance.

The mass and volume both change when changing the amount of molasses.
However, the density does not change. This is because the mass and volume increase at the same rate/proportion!

Even though there is more molasses (mass) in test tube A, the molasses also takes up more space (volume). Therefore, the spacing between those tiny particles that make up the molasses is constant (does not change).

The size or amount of a material/substance does not affect its density.
Tanya [424]4 years ago
5 0

Adding more of a substance has no effect on its density.  The formula for density is:

Density = (mass) divided by (volume).

If you doubled the volume of your sample of the substance, then you also doubled the mass of the sample.  So when you divide (mass) by (volume), you still get the same number.  The density doesn't change.


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Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. what is the approximate vertica
Serjik [45]
An initial velocity is:
v o = 25 m/s
The vertical component of the initial velocity:
v o y = v o * sin 60° =
= v o * √3 / 2 = 25 m/s * √3 / 2 = 21.65 m/s
Answer:
The approximate vertical component of the initial velocity is 21.65 m/s.
7 0
4 years ago
Read 2 more answers
A cart with a mass of 0.5 kg is at the top of the ramp. The height is 0.40m .
Tju [1.3M]

A=0.05.0M.

B=68.9244GPE.34

C=0

D it would be 79%HIGHER

3 0
3 years ago
ILI
Nikolay [14]

The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.

<u>Explanation:</u>

As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,

                  \text {Kinetic energy}=\frac{1}{2} m v^{2}

So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.  

The final kinetic energy is

\text {Kinetic energy}=\frac{1}{2} m v^{2}=\frac{1}{2} \times 600 \times 5 \times 5 = 7500 J

As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.  

                       Work done = Final Kinetic energy - Initial Kinetic energy

Thus the work utilized for moving the car is  

                         Work done = 7500 J - 0 J = 7500 J

Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.

7 0
3 years ago
Arthur and Betty start walking toward each other when they are 100 m apart. Arthur has a
Gnoma [55]
The distance covered by Arthur is
3t
The distance covered by Betty from where Arthur started is
100 - 2t
They meet each other when this distance is equal
3t = 100 - 2t
t = 20 s

Since the dog has a constant speed of 5m/s, the distance that Spot has run is
5 m/s (20s) = 100 m
6 0
3 years ago
Read 2 more answers
1 7.1.2 Quiz: Electrostatics
Veseljchak [2.6K]

Answer:

charge and distance

Explanation:

The electric force between the two particles are calculated using the formular:

F = kQ₁Q₂ / d²

where:

F = force.

k= Coulomb's law constant.

Q1 and Q2 are the charges.

d= distance.

the equation above is called Coulomb's law.

It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.

so the correct option is charge and distance.

5 0
2 years ago
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