Answer:
speed of flow of blood in the blocked portion of the vessel is 9.18 vo
Explanation:
given data
diameter of the vessel = 67.0 %
to find out
what is its speed v expressed as a multiple of vo
solution
we know here that Plaque decreases diameter of the vessel by 67%
s here diameter in the blocked portion = 33% of diameter in unblocked portion so
we will apply here Continuity equation that is express as
Ao×Vo = A1×V1 ...................1
here Ao is Cross-sectional area of the cylindrical blood vessel that is =
and do is Diameter of the cylindrical blood vessel and vo is Speed of flow of blood in the blood vessel
and d1 is diameter of the vessel in the blocked portion of the vessel that is = 0.33 do and A1 is cross section area of the vessel in the blocked portion that is = and v1 is Speed of flow of blood in the blocked portion of the vessel
so now we put value in equation 1 we get
Ao×Vo = A1×V1
× vo = × v1
do²×vo = d1²×v1
do²×vo = d1²×v1
do²×vo = (0.33 do)²×v1
solve it we get
v1 = 9.18 vo
so speed of flow of blood in the blocked portion of the vessel is 9.18 vo
Answer:
no work was done.
Explanation:
just because you put effort into something doesn't mean it pays off.
because the displacement was 0, the work is 0 too.
C. movement of glaciers.
Good Luck.
Answer:
Angular acceleration of the disk ∝ = K
Explanation:
Given that;
Angular velocity function given by ω = Kt + L
Angular acceleration of the disk at t=T is = ?
Now,
Angular velocity;
ω = Kt + L
Angular acceleration is;
∝ = dω / dt
= ( Kt + L )
At t = T
∝ = K
Because ∝ is not dependent on t
Therefore
Angular acceleration of the disk ∝ = K
Answer:
Explanation:
Given that,
Mass m = 2kg
Initial Velocity Vi = 3m/s
Force applied. = 4N
Distance cause by the force applied d = 5m
a. Work done by the force applied?
Work done by force applied can be determined by
W = F×d•Cosx
Where x is direction is the force and displacement
The force and displacement are in the same direction, then, x =0°
W = F×d•Cosx
W = 4×5Cos0
W = 20J.
b. Final velocity
The change in kinetic energy is equal to work done
∆K.E = W
½mVf² - ½mVi² = W
½mVf² = ½mVi² + W
½ × 2 Vf² = ½ × 2 × 3² + 20
Vf² = 9+20
Vf² = 29
Vf = √29
Vf = 5.39m/s
The final velocity is 5.39m/s