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3 years ago

The radius of a circle of area A and circumference C is doubled. find the new circumference of the circle in terms of C.

1 answer:

3 0

If the radius of a circle of area A and circumference C is doubled, the new circumference of the circle, in terms of C, will be equal to 2C.

The area (A) of a circle is given by:

$A = \pi r^{2}$ (1)

And a circumference (C) is:

$C = 2\pi r$ (2)

Where:

r: is the radius

If the radius of a circle and circumference is doubled, the new circumference of the circle is:

$C_{2} = 2 (2 \pi r) = 2C$

Therefore, the new circumference of the circle in terms of C is equal to 2C.

To find more about circumference, go here: brainly.com/question/4268218?referrer=searchResults

I hope it helps you!

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Suppose that the height of the incline is h = 14.7 m. Find the speed at the bottom for each of the following objects. 1.solid sp

tensa zangetsu [6.8K]

Answer:

1. 14.4 m/s 2. 13.2 m/s 3. 12.0 m/s 4. 13.9 m/s

Explanation:

Assuming no friction present, the different objects roll without slipping, so there is a constant relationship between linear and angular velocity, as follows:

ω= v/r

If no friction exists, the change in total kinetic energy must be equal in magnitude to the change in the gravitational potential energy:

∆K = -∆U

½ *m*v² + ½* I* ω² = m*g*h

Simplifying and replacing the value of the angular velocity:

½ * v² + ½ I *(v/r)² = g*h (1)

In order to answer the question, we just need to replace h by the value given, and I (moment of inertia) for the value for each different object, as follows:

Solid Sphere I = 2/5* m *r²

Replacing in (1):

½ * v² + ½ (2/5 *m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

v = √(10/7*9.8 m/s2*14.7 m) = 14. 4 m/s

Spherical shell I=2/3*m*r²

Replacing in (1):

½ * v² + ½ (2/3 *m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

v = √(6/5*9.8 m/s2*14.7 m) = 13.2 m/s

Hoop I= m*r²

Replacing in (1):

½ * v² + ½ (m*r²) *(v/r)² = g*h

Replacing by the value given for h, and solving for v:

v = √(9.8 m/s2*14.7 m) = 12.0 m/s

Cylinder I = 1/2 * m* r²

Replacing in (1):

½ * v² + ½ (1/2 *m*r²) *(v/r)²= g*h

Replacing by the value given for h, and solving for v:

v = 2*√(1/3*9.8 m/s2*14.7 m) = 13.9 m/s

5 0

3 years ago

From her bedroom window a girl drops a water-filled balloon to the ground, 4.60 m below. If the balloon is released from rest, h

anygoal [31]

Known variables
d=4.6m
initial velocity=0m/s
downward acceleration=-9.8m/s2

d=1/2gt2
4.6=1/2 -9.8 t2
t=0.93s

8 0

3 years ago

The igneous rocks which were deposited on the surface and then cooled are known as __________.

mr Goodwill [35]

The igneous rocks which were deposited on the surface and then cooled are known as extrusive. These rocks are a result of a magma reaching the surface of the Earth which cools the magma quickly. Examples are rhyolite, basalt, obsidian and andesite.

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3 years ago

2. A test reveals that 150 J of work is required to lift an object 3 m at a

Nuetrik [128]

Answer:

50N

Explanation:

W=Fd

150=F(3)

50N=F

7 0

2 years ago