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3 years ago

The radius of a circle of area A and circumference C is doubled. find the new circumference of the circle in terms of C.

1 answer:

3 0

If the radius of a circle of area A and circumference C is doubled, the new circumference of the circle, in terms of C, will be equal to 2C.

The area (A) of a circle is given by:

$A = \pi r^{2}$ (1)

And a circumference (C) is:

$C = 2\pi r$ (2)

Where:

r: is the radius

If the radius of a circle and circumference is doubled, the new circumference of the circle is:

$C_{2} = 2 (2 \pi r) = 2C$

Therefore, the new circumference of the circle in terms of C is equal to 2C.

To find more about circumference, go here: brainly.com/question/4268218?referrer=searchResults

I hope it helps you!

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A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo

Rasek [7]

Answer:

$t=12.25\ seconds$

Explanation:

Diagonal Launch

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

$x=v_ocos\theta t$

$\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}$

Where vo is the magnitude of the initial velocity, $\theta$ is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

$\displaystyle t=\frac{v_osin\theta}{g}$

There are two times where the value of y is $y_o$ when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making $y=y_o$

$\displaystyle y_o=y_o+v_osin\theta\ t-\frac{gt^2}{2}$

Removing $y_o$ and dividing by t (t different of zero)

$\displaystyle 0=v_osin\theta-\frac{gt}{2}$

Then we find the total flight as

$\displaystyle t=\frac{2v_osin\theta}{g}$

We can easily note the total time (hang time) is twice the maximum (apex) time, so the required time is

$\boxed{t=24.5/2=12.25\ seconds}$

4 0

3 years ago

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Dmitry [639]

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5 0

2 years ago

Read 2 more answers

The process that enhances some properties of an object at the expense of other properties is called:

lidiya [134]

Answer:

The answer is: letter a, pop-out effect.

Explanation:

The "pop-out effect" is a phenomenon which allows the person's precognitive processes to detect a visual stimulus that is potentially the most meaningful one in a person's spatial field of attention. The pop-up effect occurs when a person distinguishes one object from the rest.

For example, when a child chooses among pictures in different colors, it is common for the child to point at colored pictures rather than grayscale pictures. This is an example of a pop-out effect. The properties of the colored pictures is more preferred by the child thus, causing him not to choose or mind the grayscale images.

Thus, this explains the answer.

6 0

3 years ago

At what speed does a typical electron pass by any given point in the wire?

attashe74 [19]

A 5.00 A current runs through a 12 gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5*10^28 free electrons per cubic metre.

a) How many electrons pass through the light bulb each second?

b) What is the current density in the wire? (answer in A/m^2)

c) At what speed does a typical electron pass by any given point in the wire? (answer in m/s)

a) 5.0 A = 5.0 C/s
. Number of electrons in 5.0C = 5.0 / 1.60^-19 = 3.125^19
. 5.0 A ►= 3.125^19 electrons/s

b) A/m² = 5.0 / π(1.025^-3 m)² .. .. ►= 1.52^6 A/m²

c) Charge density (q/m³) = 8.50^28 e/m³ x 1.60^-19 = 1.36^10 C/m³

(q/m³)(m²)(m/s) = q/s (current i in C/s [A])
(m²) = Area
(m/s) = mean drift speed

(q/m³)(A)(v) = i

v = i.[(q/m³)A]ˉ¹

v = 5.0 [1.36^10 * π(1.025^-3 m)²]ˉ¹.. .. ►v = 1.10^-4 m/s

7 0

3 years ago

When a resistor is connected to a 12 volt source, it draws a 185 mA current. what's the resistance? (I said 65 ohms). the same r

lyudmila [28]

Resistance-1 = (voltage-1) / (current-1) =

(12 V) / (0.185 A) = 64.9 ohms .

Resistance-2 = (voltage-2) / (current-2) =

(90 V ) / (1.25 A) = 72 ohms .

The resistance changed between situation-1 and situation-2 .
How did that happen ?

Power = (voltage) x (current)

Power-1 = (12) x (0.185) = 2.22 watts

Power-2 = (90) x (1.25) = 112.5 watts

The poor resistor dissipated 51 times as much power during
the second trial. It got all heated up, and its resistance went
through the roof.

Carbon resistors behave nicely and reliably, until you try to
toast bread or light up your bedroom with them.

8 0

3 years ago