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3 years ago

The radius of a circle of area A and circumference C is doubled. find the new circumference of the circle in terms of C.

1 answer:

3 0

If the radius of a circle of area A and circumference C is doubled, the new circumference of the circle, in terms of C, will be equal to 2C.

The area (A) of a circle is given by:

$A = \pi r^{2}$ (1)

And a circumference (C) is:

$C = 2\pi r$ (2)

Where:

r: is the radius

If the radius of a circle and circumference is doubled, the new circumference of the circle is:

$C_{2} = 2 (2 \pi r) = 2C$

Therefore, the new circumference of the circle in terms of C is equal to 2C.

To find more about circumference, go here: brainly.com/question/4268218?referrer=searchResults

I hope it helps you!

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What can you say about the magnitudes of the forces that the balloons exert on each other?

maxonik [38]

Answer:

$F_G=G. \frac{m_1.m_2}{R^2}$ gravitational force

$F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}$ electrostatic force

Explanation:

The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.

The Mutual force of gravitational pull that they exert on each other can be given as:

$F_G=G. \frac{m_1.m_2}{R^2}$

where:

$G=$ gravitational constant $=6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}$

$m_1\ \&\ m_2$ are the masses of individual balloons

$R=$ the radial distance between the center of masses of the balloons.

But when there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.

Given as:

$F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}$

where:

$\rm \epsilon_0= permittivity\ of\ free\ space$

$q_1\ \&\ q_2$ are the charges on the individual balloons

R = radial distance between the charges.

3 0

3 years ago

1. Is The larger the mass the greater the acceleration is on a smaller object?

zheka24 [161]

Answer:No,a smaller object would have more acceleration because it would take less force to move.

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3 years ago

Two cylinders with the same mass density rhoC = 713 kg / m3 are floating in a container of water (with mass density rhoW = 1025

Tanzania [10]

Answer:

Explanation:

Given

density of cylinder is $\rho _c=713 kg/m^3$

Length of first cylinder is $L_1=20 cm$

radius $r_1=5 cm$

For cylinder 2 $L_2=10 cm$

$r_2=10 cm$

$h_1$ and $h_2$ are the height above water

as object is floating so its weight must be balanced with buoyant force

$\rho _c\frac{\pi }{4}d_1^2L_1g=\rho _w\frac{\pi }{4}d_1^2(L_1-h_1)g----1$

For 2nd cylinder

$\rho _c\frac{\pi }{4}d_2^2L_2g=\rho _w\frac{\pi }{4}d_2^2(L_2-h_2)g----2$

Dividing 1 and 2 we get

$\frac{L_1}{L_2}=\frac{L_1-h_1}{L_2-h_2}$

$\frac{20}{10}=\frac{20-h_1}{10-h_2}$

$2h_2=h_1$

$\\\Rightarrow\frac{h_2}{h_1}=\frac{1}{2}$

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3 years ago

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