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liberstina [14]
2 years ago
14

Can someone explain to me how do you do fractions? And yes I already gotten the answer I just want to know how to do it

Mathematics
1 answer:
sasho [114]2 years ago
6 0

do you want to know for the multipaction and subtraction and addition

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Help please anyone:)
Anna007 [38]
The answer is -0.75.
7 0
3 years ago
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The yearbook club had a meeting. The club has 30 people and three fifths of the club showed up for the meeting how many went to
cestrela7 [59]

Answer:

there are 45 people in the group

2/3xA=30

2A=30x3

A=90/2

A=45

8 0
3 years ago
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SOMEONE PLEASE HELP!<br><br> what is 2.3% written as a desimal
monitta

Answer:

2.3% as a decimal is 0.023


8 0
3 years ago
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Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = -2x 4 6x 3y =
wariber [46]

The missing value is 12 in a system of equations with infinitely many solutions conditions.

It is given that in the system of equations there are two equations given:

\rm y =n -2x+4\\\rm and \\\rm 6x+3y= ?

It is required to find the missing value in the second equation.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

We have equations:

\rm y = -2x+4 ....(1)\\  \\\rm 6x+3y= ?  ....(2)

Let's suppose the missing value is 'Z'

We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.

From equation (1)

\rm y = -2x+4 \\\\\rm 2x+y=4(multiply both the sides by 3)

\rm 6x+3y=12 ...(3)

By comparing the equation (2) and (3), we get

M = 12

Thus, the missing value is 12 in a system of equations with infinitely many solutions conditions.

Learn more about the linear equation.

brainly.com/question/11897796

8 0
2 years ago
28, 33, 88, 81, 40, 25, 41<br> Mean median mode and range
PolarNik [594]

Hello!

Step-by-step explanation:

Mean: 48

Median: 40

Mode: None

Range: 63

Hope this helps!

3 0
2 years ago
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