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kozerog [31]
3 years ago
13

I need help please i need it today

Chemistry
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

what help.....

i don't understand your question what help....

can you told me what help...

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How would Bohr model show the protons in a carbon atom
MariettaO [177]

Answer:

The Bohr model show the protons in a carbon atom using the model;  "Electrons move in fixed orbits around a nucleus of protons and neutrons."

According to Bohr's model of the atoms, the Rutherford model is basically correct. This implies that Bohr model accepts the idea of a nucleus containing nucleons(protons and neutrons).

In addition, the model also postulates that electrons are found in fixed orbits. These fixed orbits are called energy levels or shells.

A graphic description of this is shown in the image attached to this answer.

Learn more: brainly.com/question/3964366

Explanation:

6 0
2 years ago
A potassium-40 sample starts with 50 atoms, and 1.25 billion years later, there are 25 atoms. What is the half-life of potassium
guapka [62]
D. 1.25 billion years
5 0
3 years ago
Help!!! Acids and Bases
valentina_108 [34]
ACID: A substance that accepts a lone pair of electrons

BASE: A substance that donates a lone pair of electrons

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4 0
3 years ago
Read 2 more answers
Plz answer the question in the picture.
astra-53 [7]

Answer:

a

Explanation:

a mixture is a material made up of two or more different substances which are not chemically combined. A mixture is the physical combination of two or more substances in which the identities are retained and are mixed in the form of solutions, suspensions and colloids.

5 0
3 years ago
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Calculate the concentration of all species in a 0.160 m solution of h2co3.
enot [183]

             H₂CO₃ ⇔       HCO₃⁻   +     H⁺

I            0.160               0                 0

C            -x                  +x               +x

E          0.160-x          +x                +x

Ka1 = [HCO₃⁻][H⁺] / [H₂CO₃]

4.3 x 10⁻⁷ = x² / (0.160-x)   (x is neglected in 0.160-x = 0.160)

x² = 6.88 x 10⁻⁸

x = 2.62 x 10⁻⁴

             HCO₃⁻    ⇔            CO₃⁻²    +   H⁺

I          2.62 x 10⁻⁴               0                2.62 x 10⁻⁴

C          -x                            +x              +x

E       2.62 x 10⁻⁴ - x           +x              2.62 x 10⁻⁴ + x

Ka2 = [CO₃⁻²][H⁺] / [HCO₃⁻]

5.6 x 10⁻¹¹ = x(2.62 x 10⁻⁴ + x) / (2.62 x 10⁻⁴ - x)

x = 5.6 x 10⁻¹¹

Thus,

[H₂CO₃] = 0.160 - (2.62 x 10⁻⁴) = 0.16 M

[HCO₃⁻] = 2.62 x 10⁻⁴ - ( 5.6 x 10⁻¹¹) = 2.6 x 10⁻⁴ M

[CO₃⁻²] = 5.6 x 10⁻¹¹ M

[H₃O⁺] = 2.62 x 10⁻⁴ + 5.6 x 10⁻¹¹ = 2.6 x 10⁻⁴ M

[OH⁻] = 3.8 x 10⁻¹¹

8 0
3 years ago
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