Which statement best explains the formation and distribution of oil?

Compare and contrast protons, neutrons, and electrons, nucleus, electron cloud and include definition charge and position in the

taurus [48]

Answer: protons are located in the nucleus and have a positive charge. neutrons are also located in the nucleus and have a neutral charge. electrons are located in the electron cloud and have a negative charge. the electron cloud surrounds the nucleus in an atom.

Explanation:

8 0

3 years ago

Need help with question

Lynna [10]

Answer:

C

Explanation:

it is the correct binding type.

7 0

3 years ago

6. This part of Earth's atmosphere blocks the sun's harmful rays. (4 points)

Mrrafil [7]

Stratosphere:) hope this helped

7 0

2 years ago

Read 2 more answers

What is the result when earth layers experience extension stress? Question 2 options:

Vika [28.1K]

Answer:

stretching and thinning of the Earth's crust occurs.

Explanation:

The result of the extension stress on Earth layers is the stretching and thinning of the Earth's crust occurs.

When there is a stress on the Earth's layers, the Earth's crust experiences the phenomena of stretching and thinning.

4 0

2 years ago

4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

4 0

3 years ago