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Zanzabum
3 years ago
12

The group that does not receive a treatment during an experiment is called the?

Chemistry
1 answer:
REY [17]3 years ago
5 0
Independent group 123456789
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on 1: A piece of unknown metal weighs 348 g. When the metal piece absorbs 6.64 kJ of heat, its temperature increases from 22.4 °
Ede4ka [16]

Answer:

.900 J / g-C°

Explanation:

I assume you are looking for the specific heat of the metal

Specific heat =  J / g-C

                      = 6640 J / 348 g[ (43.6 - 22.4) ] = .900 J / g-C

6 0
2 years ago
Read 2 more answers
Construct <br> an isotope has 17 protons 20 neutrons and 18 electrons
ASHA 777 [7]
Add proton + neutrons = Mass 37

Proton is same as your atomic mass= 17

If you go on the periodic table look up 17 and it will give u the letter.
4 0
3 years ago
An atom has the electron arrangement 2,8. What will it do to gain a full
777dan777 [17]
The answer is B) gain 8 electrons
8 0
3 years ago
Billy drives a water balloon from the roof of his house since the balloon began with an original Velocity of zero how far above
Artyom0805 [142]
3.7 I thank is the answer
6 0
3 years ago
Give regents and mechanism
Kryger [21]

Answer:

Reagents: 1) BH_3 2) H_2_O2, OH^-

Mechanism: Hydroboration

Explanation:

In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.

The <u>first step</u> of this reaction is the addition of borane (BH_3) to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "BH_2-O-OH". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of OH^- on the O-BH_2 to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.

See figure 1

I hope it helps!

4 0
3 years ago
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