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fgiga [73]
3 years ago
13

help me please. In a certain organic compound, one of the carbon atoms is bonded to two atoms: a hydrogen atom and a carbon atom

. What type of bond exists between the two carbon atoms? Single covalent Triple covalent Ion dipole Ionic
Chemistry
1 answer:
balu736 [363]3 years ago
6 0

Answer:

The answer would be Triple Covalent!

Explanation:

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Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi
marissa [1.9K]

Answer:

New net worth to three significant figures = $80.2 billion

Dollars are given to charity = $100,250,000

Explanation:

Net worth = $77.0 billion

stock Gains = $3.20 billion

New net worth = $77.0 billion + $3.20 billion = $80.20 billion

New net worth to three significant figures = $80.2 billion

One-eighth of a percent = (1/8 x 1) / 100 = 0.00125

Dollars are given to charity = 0.00125 X $80.2 billion = $100,250,000

Or

$80,200,000,000/100 = $802,000,000

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3 years ago
All of the following will be damaging to the environment except
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Which planets' orbits is the belt located between the main asteroid belt?
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<span>circumstellar is the answer</span>
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3 years ago
How many grams are in 11.9 moles of chromium?
raketka [301]

Explanation:

It is known that one mole of chromium or molar mass of chromium is 51.99 g/mol.

It is given that number of moles is 11.9 moles.

Therefore, calculate the mass of chromium in grams as follows.

     No. of moles = \frac{mass in grams}{Molar mass}

    mass in grams = No. of moles × Molar mass

                             = 11.9 moles × 51.99 g/mol

                             = 618.68 g

Thus, we can conclude that there are 618.68 g in 11.9 moles of chromium.

7 0
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The full question is shown in the image attached

Answer:

See explanation

Explanation:

In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.

When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;

1. 2-methyl propane

2. 2,4-dimethyl heptane

3. 2,2,3,3-tetramethyl butane

4. 5-ethyl-2,4-dimethyl octane

5 0
3 years ago
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