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melisa1 [442]
3 years ago
9

Compare using <, >, or =.

Chemistry
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

63cm < 6m

5g > 508mg

1500mL = 1.5 L

536cm = 53.6dm

43mg < 5g

3.6m> 36cm

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A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
Ulleksa [173]

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




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Methyl tertiary-butyl ether (MTBE) is an organic compound that has been in use since the late 1970s. Read the article to learn m
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3 years ago
Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.
MrRissso [65]
<h2>Answers to the rest of the assignment:</h2>

**Check for proof photos at the bottom.**

__________________________________________________________

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.  

Cranberry juice at the store

A. homogeneous

C. solution

Smoke  

B. heterogeneous  

D. colloid

__________________________________________________________

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.  

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B. heterogeneous  

E. suspension

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B. heterogeneous  

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__________________________________________________________

Shown here is a person shaving.  Under magnification, the shaving foam might look like the image above the shaver. What type of mixture does the foam demonstrate? Give your reasoning.

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On the next slide, you can select any answers you want, or you can select nothing. There's no wrong answer.  

__________________________________________________________

A student squeezes several oranges to make a glass of orange juice. The juice contains pieces of orange pulp mixed with the juice. Explain why this drink can be considered a combination of a suspension and a solution.

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On the right side, you can also select any answers or none at all. There is no wrong answer.

__________________________________________________________

<h2>Explanation:</h2>

There are two main types of mixtures, homogeneous mixtures and heterogeneous mixtures. The components of a homogeneous mixture are evenly distributed throughout the mixture. The properties of a mixture are the same everywhere. The components of a heterogeneous mixture are not evenly distributed. Different regions of this mixture have different   properties.

Particles in a homogeneous mixture do not settle down or separate when left alone. Particles in a heterogeneous mixture eventually separate or settle when left alone.

  • Colloids are a type of heterogeneous mixture that do not naturally settle out quickly, and can be separated with different methods.
  • A suspension is another type of heterogeneous mixtures in which the components of the mixture will quickly settle out or can be filtered or separated.

Here are photos of Edge just incase.

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Answer:

Explanation:

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