Answer:
A 17 year old with a resting heart rate of 62 bpm has a maximum hearth rate of 203 bpm, a hearth rate reserve of 141 bpm and target hearth rate between 161 and 182 bpm
Explanation:
Target heart rate is a measure used to calculate the range of heart rate that should be maintained during intense exercise.
Knowing a person's age and resting heart rate (RHR), a target heart rate calculation can be made from the maximum heart rate (MHR) and the hearth rate reserve (HRR)
Data:
- Age: 17 years old
- RHR: 68 bpm
The maximum heart rate is calculated by subtracting age from a constant value of 220, so:
- MHR = 220 - age
- MHR = 220 - 17
- MHR = 203 bpm
HRR is calculated by subtracting the resting heart rate (RHR) from the MHR value:
- HRR = MHR - RHR
- HRR = 203 - 62
- HRR = 141 bpm
THR is obtained by multiplying the HRR by 0.7 and 0.85, to obtain the range of heart rate in which the exercise can be performed.
- THR lower limit = (HRR x 0.7) + RHR Lower THR = (141 x 0.7) + 62 = 160.7 ≈ 161 bpm
- THR top limit = (HRR x 0.85) + RHR THR top = (141 x 0.85) + 62 = 181,85 ≈ 182 bpm
For the 17-year-old, the ideal target heart rate for an intense exercise is between the values of 161 and 182 bpm.
The answer is B because a virus would be more effective
<u>ANSWER:
</u>
Medicalization is the process by which the conditions and problems of a human are been identified as a disease according to the symptoms. These diseases are needed to be diagnosed and prevented through treatment.
<u>EXPLANATION:</u>
When I tend to find the disability of a patient, my perception of the situation changes from being a normal person to a caring one enriched with helping tendency. What I believe is different from what I genuinely am.
Answer: 2.6 ml of chlorpromazine are administered.
Explanation:
Given stock solution of chlorpromazine, 3.2 %(m/v) i.e 3.2 grams of chlorpromazine are dissolved in 100 ml of solution
We need to find the volume of solution that can contain 0.083 grams of chlorpromazine.
By applying unitary method, we get:
3.2 grams of chlorpromazine is present in 100 mL of solution.
So, 0.083 grams of chlorpromazine will be present in = 
of solution.
Hence, the given amount of chlorpromazine will be present in 2.6 mL of solution and thus 2.6 ml are administered.
Correct answer is A. True
