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butalik [34]
3 years ago
8

which describes the relationship between the frequency, wavelength, and speed of a wave as the wave travels through diffrent med

ia?
Physics
1 answer:
Goryan [66]3 years ago
5 0
As speed changes, wavelength changes, and frequency remains the same
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If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t
STatiana [176]

Answer:

The velocity is  4.6 m/s^2

Explanation:

Given:

Force = 500N

Distance  s= 0

To find :

Its velocity at s = 0.5 m

Solution:

\sum F_{x}=m a

F\left(\frac{4}{5}\right)-F_{S}=13 a

500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a

400-(500 s)=13 a

a = \frac{400 -(500s)}{13}

a = (30.77 -38.46s) m/s^2

Using the relation,

a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}

a=v \frac{d v}{d s}

v d v=a d s

Now integrating on both sides

\int_{0}^{v} v d v=\int_{0}^{0.5} a d s

\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s

\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}

\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]

\left[\frac{v^{2}}{2}\right]=[15.385-4.807]

\left[\frac{v^{2}}{2}\right]=10.578

v^{2}=10.578 \times 2

v^{2}=21.15

v = \sqrt{21.15}

v = 4.6 m/s^2

8 0
3 years ago
a 2000 kg car moving down the road runs into a 5000 kg stationary suv. The car applies a force of 1400 n on the suv what is the
masha68 [24]

Answer:

F_suv= 49050 N

Explanation:

We are told that a 2000 kg car moving down the road runs into a 5000 kg stationary suv. The car applies a force of 1400 N on the suv.

Now, according Newton's first law of motion, an object will continue in it's present state of rest except it is acted upon by an external body.

This means the force acting on the stationary Suv is force of gravity.

Thus; F_suv = 5000 × 9.81

F_suv= 49050 N

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It falls duh.. ..............
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How do you calculate the slop of a line
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To calculate the slope of a line you need only two points from that line, (x1, y1) and (x2, y2). The equation used to calculate the slope from two points is: On a graph, this can be represented as: There are three steps in calculating the slope of a straight line when you are not given its equation.
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A cart of mass m moving right at speed v collides with an identical cart moving right at half the speed. the carts stick togethe
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