Answer:
The velocity is 
Explanation:
Given:
Force = 500N
Distance s= 0
To find :
Its velocity at s = 0.5 m
Solution:






Using the relation,



Now integrating on both sides


![\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D_%7B0%7D%5E%7B2%7D%3D%5Cleft%5B%5Cleft%2830.77%20s-19.23%20s%5E%7B2%7D%5Cright%29%5Cright%5D_%7B0%7D%5E%7B0.5%7D)
![\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D%3D%5Cleft%5B%5Cleft%2830.77%280.5%29-19.23%280.5%29%5E%7B2%7D%5Cright%29%5Cright%5D)
![\left[\frac{v^{2}}{2}\right]=[15.385-4.807]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D%3D%5B15.385-4.807%5D)
![\left[\frac{v^{2}}{2}\right]=10.578](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bv%5E%7B2%7D%7D%7B2%7D%5Cright%5D%3D10.578)




Answer:
F_suv= 49050 N
Explanation:
We are told that a 2000 kg car moving down the road runs into a 5000 kg stationary suv. The car applies a force of 1400 N on the suv.
Now, according Newton's first law of motion, an object will continue in it's present state of rest except it is acted upon by an external body.
This means the force acting on the stationary Suv is force of gravity.
Thus; F_suv = 5000 × 9.81
F_suv= 49050 N
To calculate the slope of a line you need only two points from that line, (x1, y1) and (x2, y2). The equation used to calculate the slope from two points is: On a graph, this can be represented as: There are three steps in calculating the slope of a straight line when you are not given its equation.
<span>After collison they stick together and have same velocity Vf
From the momentum conservation,
(m1 + m2)Vf = m1v1 + m2v2
Second is moving with half of first cart speed, (m1 + m2)Vf = m1v + m2v / 2
2(m1 + m2)Vf = (2m1v + m2v) =>Vf = ((2m1 + m2) v) / 2(m1 + m2)
Identical carts so m1 = m2 = m
vf = 3mv / 4m => Vf = 3v / 4</span>