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Leokris [45]
3 years ago
13

Jerrod’s family drove 1,778 miles from Denver, Colorado, to New York City. They averaged 61.7 miles per hour on the trip. Which

is the best estimate of the number of hours the family drove?
3 hours
4 hours
30 hours
40 hours
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
6 0

Answer:

30 hours

Step-by-step explanation:

Distance = Speed * Time

We can use that formula to plug in the numbers given.

1778mi = 61.7mph * Time

1778/61.7 = 28.817 (approx.)

So the answer will be about 30 hours

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the lombaro family went out to dinner and the cost of their meal was 62% if they left a 20% tip how much did they leave
swat32

Answer:

they left a $1.24 tip

Step-by-step explanation:


3 0
3 years ago
Solve for x show all your work. 10x + 15 = 5x - 10​
sdas [7]

Answer:

x=-5

Step-by-step explanation:

10x + 15 = 5x-10

-5x            -5x

5x+15 = -10

    -15     -15

5x = -25

/5      /5

x = -5

7 0
4 years ago
It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

  =\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

   = 8

Thus, the degrees of freedom of the test is 8.

8 0
3 years ago
What is the value of (−23) –[(−25) – {(−17) –(−19)}
o-na [289]
The answer is four.
5 0
3 years ago
NEED HELP
zzz [600]
D for the same reason percents

6 0
3 years ago
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