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VladimirAG [237]
4 years ago
6

!Select ALL and ANY that apply!

Physics
2 answers:
BaLLatris [955]4 years ago
8 0

Nuclear Reactor is made to use the energy which is released due to nuclear fission reaction.

These chain reactions are very fast and they are used with some components which can control these reactions otherwise these reaction will start with high rate and could not be controlled after that.

In order to control these reactions we need to control the high energy particles which can stimulate these reactions

These are neutrons which act as catalyst of these nuclear reactions and these reactions can be control by controlling the numbers of neutrons

These neutrons can be absorbed by some mechanism and the rods which are used to absorb these high energy neutrons are known as control rods.

So correct answer must be control rods

Romashka-Z-Leto [24]4 years ago
3 0
The answer is B. Control rods :)
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An ethylene glycol solution contains 25.4 g of ethylene glycol (C2H6O2) in 89.0 mL of water. (Assume a density of 1.00 g/mL for
Vaselesa [24]

Answer:

-7.44°C

Explanation:

Calculate the molality of the solution. Use the density of the solvent(water) as a conversion factor in order to convert from millilitres of solvent to grams of solvent. Then convert grams into kilograms. Finally, use the molar mass of ethylene glycol as a conversion factor to convert from grams to moles of ethylene glycol.  

m = 25.4 g C2H6O2/89.0 mL solv

   = 4.6321 C10H8O

Compute the freezing-point depression.  

ΔT_f=K_f*m ==> (1.86°C)*(3.9996 m)

       =7.44°C

Compute the freezing point of the solution by subtracting the freezing-point depression to the freezing point of the pure solvent.  

 freezing point =0.0°C-ΔT_f

                        = -7.44°C

8 0
3 years ago
At a certain location, Earth's magnetic field of 34 µT is horizontal and directed due north. Suppose the net field is zero exact
zheka24 [161]

Answer:

a) I = 13.77 A

b) 0 ° or to the East

Explanation:

Part a

The magnetic field by properties would be 0 at the radius on this case r =8.1 cm.Analyzing the situation the wirde would produce a magnetic field equals in magnitude to the magnetic field on Earth by with the inverse direction.

The formula for the magnetic field due to a wire with current is:

B = \frac{\mu_0 I}{2 \pi r}

In order to have a value of 0 for the magnetic field at the radius then we need to have this balance

B (r=8.1) = B (Earth)

Replacing:

B = \frac{\mu_0 I}{2 \pi r)}= B_{Earth}

Solving from I, from the last equation we got:

I = \frac{2 \pi r B_{earth}}{\mu_0}

I=\frac{2 \pi 0.081 m (34 x 10^{-6} T)}{4 \pi x 10^{-7} Tm/A} = 13.77 A

Part b

We can use the right hand rule for this case.

The magnetic field of the wire would point to the South, because the magnetic field of the earth given points to the North. Based on this the current need's to flow from West to East in order to create a magnetic field pointing to the south, because the current would be perpendicular to the magnetic field created.

8 0
3 years ago
A proton is released from rest at x=5 cm. what direction does it move?
Veronika [31]
Down to the left, down the the right, criss cross!
6 0
3 years ago
Where are the longest continuous mountain ranges on Earth located?
andrew-mc [135]
It is located through seven countries in South America which are Venezuela, Colombia, Ecuador, Peru, Bolivia, Chile and Argentina. This is the Andes Mountains which is about 7000 km long. This is known as the world's longest mountain range.
6 0
3 years ago
A magnet in the form of a cylindrical rod has a length of 7.30 cm and a diameter of 1.5 cm. It has a uniform magnetization of 5.
yulyashka [42]

Answer:

Magnetic dipole moment is 0.0683 J/T.

Explanation:

It is given that,

Length of the rod, l = 7.3 cm = 0.073 m

Diameter of the cylinder, d = 1.5 cm = 0.015 m

Magnetization, M=5.3\times 10^3\ A/m

The dipole moment per unit volume is called the magnetization of a magnet. Mathematically, it is given by :

M=\dfrac{\mu}{V}

\mu=M\times \pi r^2\times l

Where

r is the radius of rod, r = 0.0075 m

\mu=5.3\times 10^3\ A/m\times \pi (0.0075)^2\times 0.073\ m

\mu=0.0683\ J/T

So, its magnetic dipole moment is 0.0683 J/T. Hence, this is the required solution.

6 0
3 years ago
Read 2 more answers
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