(g-5h)(g-7h). Hope this helps!
Answer:
<h3>B. </h3>
Step-by-step explanation:
<h3>Because A. Is not pentomino </h3><h3>C. Is not pentomino</h3><h3>D. There are no pentomino</h3>
(7) m∠A = 52°
(8) m∠B = 117°
Solution:
(7) Let us first define the supplementary and complementary angles.
Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°
Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°
Given supplement of 142° = 180° – 142°
= 38°
Complement of ∠A = Supplement of 142°
⇒ Complement of ∠A = 38°
Measure of ∠A = 90° – 38°
= 52°
Hence m∠A = 52°.
(8) Given complement of 27° = 90° – 27°
= 63°
Supplement of ∠B = Complement of 27°
⇒ Supplement of ∠B = 63°
Measure of ∠B = 180° – 63°
= 117°
Hence m∠B = 117°.
Answer: The fraction of set of twins=
The fraction of sets of triplets=
The fraction of set of quadruplets=
Step-by-step explanation:
Given: The number of set of twins=5
The number sets of triplets = 2
The number of set of quadruplets=1
⇒ The total number of multiple birth students =5+2+1=8
∴ The fraction of set of twins=
∴ The fraction of sets of triplets=
∴ The fraction of set of quadruplets=
Answer:
the answer is x= 2,-4
Step-by-step explanation:
zeros = 2, -4
