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kirill115 [55]
3 years ago
7

Type a digit that makes this statement true. 1,878,66 is divisible by 6. Submit

Mathematics
1 answer:
rodikova [14]3 years ago
7 0
Yes it’s true

The answer comes out as 31,311
So 1,878,66 is divisible by 6 Is TRUE


Hope this helps *smiles*
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Find the area of the triangle
Archy [21]

Step-by-step explanation:

total base length has to be found.

(√(3.6)^2+(3.25)^2+6.2)*3.25*.5=3.97

6 0
2 years ago
What are the solutions to the quadratic equation 5x2 – 8= –12x?
Tpy6a [65]

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8 0
3 years ago
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The diameter of fishing line varies. Fishing lines can have a diameter as small as 2 x 102 inch and as large as 6 x 10-2 inch. H
Reil [10]
Answer:
3 times

Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in

We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3

This means that the large diameter is 3 times the small one.

Hope this helps :)
4 0
3 years ago
The sum of four consecutive even integers is -28
mina [271]
I guess you want to find the 4 numbers

x + x + 2 + x + 4 + x + 6 = -28
4x + 12 = - 28
4x =  - 40
x = -10

so the numbers are -10, -8, -6 ,-4.

8 0
3 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
3 years ago
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