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Mariana [72]
4 years ago
13

A metal cylinder has a height of 5.40 cm , a diameter of 1.25 cm, and a mass of 42g what is the density of the metal cylinder

Chemistry
1 answer:
g100num [7]4 years ago
6 0

Answer: 3.96 g/cm³

Explanation: Solution attached:

First convert diameter into radius

Find volume of cylinder using its formula V= πr²h

Solve for density d= m/V

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NaCl has a Delta. Hfus = 30. 2 kJ/mol. What is the mass of a sample of NaCl that needs 732. 6 kJ of heat to melt completely? Use
tia_tia [17]

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

The heat of fusion has been the amount of heat required to convert  1 mole of substance into solid to liquid state.

The heat required has been given as:

Q=m\Delta H

<h3>Computation for the mass of NaCl</h3>

The given solution has heat of fusion, \Delta H_{fus}=30.2\rm kJ/mol

The heat required to melt the sample has been, Q=732.6\;\rm kJ/mol

Substituting the values for the mass of NaCl

\rm 732.6\;kJ/mol=Mass\;\times\;30.2\;kJ/mol\\\\&#10;Mass=\dfrac{732.6}{30.2}\;g\\\\&#10; Mass=24.3\;g\\

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

Learn more about heat of fusion, here:

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5 0
3 years ago
How many TOTAL carbon atoms are their in this equation? A. 1 B. 2 B.4 B. 6
telo118 [61]
What equation, love?
8 0
4 years ago
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What is the formula weight (amu) of the molecule H2O? Use atomic masses of H and O as 1.008 amu and 16.00 amu respectively. Repo
vaieri [72.5K]

Answer:

Formula weight of H₂O molecule is  18.02 amu.

Explanation:

Given data:

Formula weight of H₂O = ?

Atomic mass of H = 1.008 amu

Atomic mass of O = 16.00 amu

Solution:

Formula weight:

"It is the sum of all the atomic weight of atoms present in given formula"

Formula weight of H₂O = 2×1.008 amu + 1×16.00 amu

Formula weight of H₂O = 18.02 amu

Thus, formula weight of H₂O molecule is  18.02 amu.

6 0
3 years ago
What is the limiting reactant when 4 mol P4 and 4 mol S8 react.
In-s [12.5K]

Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

8 P₄ + 3 S₈ → 8 P₄S₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • P₄: 8 moles
  • S₈: 3 moles
  • P₄S₃: 8 moles

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?

moles of P_{4} =\frac{4 moles of S_{8} x8 moles of P_{4} }{3 moles of S_{8}}

<u><em>moles of P₄= 10.667 moles</em></u>

But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.

Learn more about the reaction stoichiometry:

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Wendy made the following diagram shown to represent the solar eclipse.
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The moon should be between the sun and Earth
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