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Mariana [72]
3 years ago
13

A metal cylinder has a height of 5.40 cm , a diameter of 1.25 cm, and a mass of 42g what is the density of the metal cylinder

Chemistry
1 answer:
g100num [7]3 years ago
6 0

Answer: 3.96 g/cm³

Explanation: Solution attached:

First convert diameter into radius

Find volume of cylinder using its formula V= πr²h

Solve for density d= m/V

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Which group or groups of atoms are the only atoms with f orbitals A. All atoms heavier than barium B. All atoms heavier than kry
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Answer:

All atoms heavier than barium

Explanation:

In the periodic table, elements are divided into blocks. We have the;

s- block elements

p- block elements

d- block elements

f- block elements

However, immediately after Barium, we now encounter elements that have f-orbitals. Barium possesses a fully filled d-orbital. Hence after it, we see elements with 4f and 5f orbitals called the Lanthanides and actinides. The elements following the lanthanide and actinide series possess completely filled f-orbitals as inner orbitals.

Hence elements heavier than barium all possess f-orbitals.

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When baking soda and vinegar react to certain surfaces up bubbles what does this mostly indicate
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a chemical reaction

Explanation:

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Acetaldehyde and butanoic acid must have the same
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7 0
3 years ago
The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2). 4Al 3O2 Right arro
Andrew [12]

Formation reaction is the formation of 1 mole of product from the constituents of the reactant molecules. The mass of oxygen that must react is 182 gm.

<h3>What is mass and molar mass?</h3>

Mass of the substance is the weight while the molar mass of the substance is the addition of the atomic mass of the individual mass of the constituent atoms of the compound or the molecule.

The chemical reaction can be shown as:

\rm 4 Al + 3 O_{2} \rightarrow 2 Al_{2}O_{3}

From the reaction, it can be said that 3 moles of oxygen are required to produce 2 moles of aluminium oxide, so x moles of oxygen will be required to produce 3.80 moles of aluminium oxide.

Solving for x:

\begin{aligned}\rm 2x &= 3.80\times 3\\\\\rm x &= \dfrac{11.4}{2}\\\\&= 5.7\;\rm mol\end{aligned}

If 1 mol of oxygen is 32 gm then 5.7 moles of oxygen will be 182.4 gm.

Therefore, option D. 182 gm is the mass of oxygen required.

Learn more about moles and molar mass here:

brainly.com/question/893495

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2 years ago
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