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Umnica [9.8K]
2 years ago
8

Ab^2-4/10 when a=4 b=6

Mathematics
1 answer:
hammer [34]2 years ago
4 0

\huge\text{Hey there!}

\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}

\large\boxed{\rm{6^2}}

\large\boxed{\rm{= 6 \times6}}

\large\boxed{\rm{= \bf 36}}

\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}

\large\boxed{\rm{4(36)}}

\large\boxed{\rm{= \bf 144}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}

\large\boxed{\rm{\bold{144} - 4}}

\large\boxed{= \rm{\bf 140}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}

\large\boxed{\rm{= \bf 14}}

\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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Elimination method<br> 4x-2y=48<br> 2x+6y=-18
yulyashka [42]
4x-2y=48\\ \\ 2x+6y=-18

First we'll multiply the second equation by -2


-2\cdot (2x+6y)=-2\cdot -18\\ \\ -4x-12y=36

Now let's add the new equation and the first one.

(4x-2y)+(-4x-12y)=48+36\\ \\ 4x-4x-2y-12y=48+36\\ \\ -14y=84\\ \\ y=\frac { 84 }{ -14 } \\ \\ y=-6

We found y's value. We'll plug it in one of the equations to find x's value.

y=-6\\ \\ 4x-2y=48\\ \\ 4x-2\cdot -6=48\\ \\ 4x+12=48\\ \\ 4x=48-12\\ \\ 4x=36\\ \\ x=\frac { 36 }{ 4 } \\ \\ x=9

Solution ;

(9, -6)


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3 years ago
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Step-by-step explanation:

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Jackie drinks a bottle of water and a bottle of orange juice every morning.
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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]

Answer:

Considering the given equation y = log_{3}x\\

And the ordered pairs in the format (x, y)

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For (\frac{1}{3}, a_{0} )

x=\frac{1}{3}

y=a_{0}

y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1

So the ordered pair will be (\frac{1}{3}, -1 )

For (1, a_{1} )

x=1

y=a_{1}

y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0

So the ordered pair will be (1, 0 )

For (3, a_{2} )

x=3

y=a_{2}

y = log_{3}x\\y = log_{3}3\\y = 1

So the ordered pair will be (3, 1 )

For (9, a_{3} )

x=9

y=a_{3}

y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2

So the ordered pair will be (9, 2 )

For (27, a_{4} )

x=27

y=a_{4}

y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3

So the ordered pair will be (27, 3 )

For (81, a_{5} )

x=81

y=a_{5}

y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4

So the ordered pair will be (81, 4 )

4 0
3 years ago
What is the solution set represented by this number line graph​
Maru [420]

Answer:

x ≥ 2

Step-by-step explanation:

The dot is shaded on the point positive 2 and the arrow is going right so its x ≥ 2.

6 0
3 years ago
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