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Umnica [9.8K]
3 years ago
8

Ab^2-4/10 when a=4 b=6

Mathematics
1 answer:
hammer [34]3 years ago
4 0

\huge\text{Hey there!}

\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}

\large\boxed{\rm{6^2}}

\large\boxed{\rm{= 6 \times6}}

\large\boxed{\rm{= \bf 36}}

\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}

\large\boxed{\rm{4(36)}}

\large\boxed{\rm{= \bf 144}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}

\large\boxed{\rm{\bold{144} - 4}}

\large\boxed{= \rm{\bf 140}}}

\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}

\large\boxed{\rm{= \bf 14}}

\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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Step-by-step explanation:

When you have a problem like this you just have to thing on a reason to multiply by a fraction and a withdrawal from the total, if you are multiplying by a fraction, that means you are dividing money, so thats why we put julie and her sisters as subjects, and her grandma givin them money is to withdraw from the total amount those $3.20

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A class has 12 boys and 4 girls. What is the ratio of boys to girls written as a decimal?
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Step-by-step explanation:

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3 years ago
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The sum of three numbers is 9.The sum of twice the first​ number, 4times the second​ number, and 5times the third number is 25.T
Karo-lina-s [1.5K]

Answer:

x = 6, y = 2, z = 1

Step-by-step explanation:

This is a system of 3 equations with 3 unknowns.  We need to first write the equations given the information and then solve them.

The first equation is the sum of 3 numbers, all unknown, is 9:

x + y + z = 9

The second equation is again a sum:

2x + 4y + 5z = 25

The third equation is the difference of only the first 2 numbers:

6x - y = 34

We will start with that last equation and solve it for y:

-y = -6x + 34 so

y = 6x - 34

Now we will go back to the first 2 equations and sub that 6x-34 in for each y.  The first equation then becomes:

x + 6x - 34 + z = 9 and 7x + z = 43

The second equation then becomes:

2x + 4(6x - 34) + 5z = 25 and 26x + 5z = 161

We will solve those 2 bold equations by addition/elimination:

  7x  +  z  =  43

26x  + 5z = 161

Multiply the first equation through by -5 to get rid of the z's.  That equation then becomes:

 -35x  -  5z  =  -215

  26x  + 5z  =  161

Adding straight down the columns gives you

 -9x  =  -54 so

x = 6

Now we can plug that x value of 6 into any equation that has an x in it:

26(6) + 5z = 161 and

156 + 5z = 161 and

5z = 5 so

z = 1.

We can use the x value only again in the equation we solved for y in the beginning:

y = 6(6) - 34 so

y = 36 - 34 and

y = 2

The solution to this system in coordinate form is

(6, 2, 1)

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Answer:B

Step-by-step explanation:

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3 years ago
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