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KiRa [710]
3 years ago
11

A shopping cart is given an initial velocity of 4 m/s and experiences a constant acceleration of 4 m/s2. What is the magnitude o

f the cart’s displacement after the first 4 s of its motion?
Physics
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

48m

Explanation:

  • Initial velocity = 4m/s
  • Acceleration = 4m/s²
  • Time = 4s
  • Displacement = ?

From Second equation of motion ,

\longrightarrow s = ut + 1/2at²

\longrightarrow s = 4*4 + 1/2*4*(4)² m

\longrightarrow s = (16 + 2 * 16) m

\longrightarrow s = ( 16 + 32 )m

\longrightarrow s = 48 m

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Answer:

0.782 s

Explanation:

The water flows horizontally from the hose, so its initial vertical velocity is 0.

Given:

y₀ = 3 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

0 m = 3 m + (0 m/s) t + ½ (-9.8 m/s²) t²

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Round as needed.

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Answer:

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Explanation:

For a linear elastic material Young's modulus is a constant that is given by:

\gamma=\frac{F/A}{\Delta L/L_0}

Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, \Delta L is the amount by which the length of the object changes and  L_0 is the original length of the object. In this case the force is the weight of the mass:

F=mg\\F=55kg(9.8\frac{m}{s^2})\\F=539N

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\gamma=\frac{F/\pi r^2}{(L_1-L_0)/L_0}\\\gamma=\frac{539N/\pi(0.045m)^2}{(5.31m-4.66m)/4.66m}\\\gamma=6.07*10^5\frac{N}{m^2}

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A projectile has an initial horizontal velocity of 34.0 M/s at the edge of a roof top. Find the horizontal and vertical componen
Sveta_85 [38]

Answer:

v_x=34 m/s

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<u>Horizontal Launch</u>

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The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

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The horizontal component of the velocity is always the same:

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