Answer: Your code returns a number of 99.123456789 +0.00455679
Ok, you must see where the error starts to affect your number.
In this case, is in the third decimal.
So you will write 99.123 +- 0.004 da da da.
But you must round your results. In the number you can see that after the 3 comes a 4, so the 3 stays as it is.
in the error, after the 4 comes a 5, so it rounds up.
So the final presentation will be 99.123 +- 0.005
you are discarding all the other decimals because the error "domains" them.
More info? I think the question is incomplete. Although, I believe the first 2 blanks are "rises"
Answer:learn vocabulary, terms,and more with flashcards, games,and other study tools.size of an objects displacement could be greater than the distance the object travels.
Explanation:
