What is the wavelength of a wave whose velocity is 8 m/s and frequency is 2 waves/second?

Why is rock away from ocean ridges older? Is it because if the rocks are away from cracks in the crust, there is no way for any

andreyandreev [35.5K]

Answer:

the rocks are away from cracks in the crust

Explanation:

The new crust is pushed away from the Ocean Ridge in both directions as newer crust is formed. This is called sea floor spreading. The crust that makes up the sea floor starts to have time to accumulate a layer of sediments as it gets older and moves away from the Ocean Ridge.

6 0

2 years ago

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When an object such as a plastic comb is charged by rubbing it with a cloth, the net charge is typically a few microcoulombs. If

masya89 [10]

The concept required to solve this problem is quantization of charge.

First the number of electrons will be calculated and then the total mass of the charge.

With these data it will be possible to calculate the percentage of load in the mass.

$Q= ne$

Here Q is the charge, n is the number of electrons and e is the charge on the electron

$n = \frac{Q}{e}$

Replacing,

$n = \frac{4*10^{-6}C}{1.6*10^{-19}}$

$n = 2.5 * 10^{13}77$

According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron

The total mass of the charge is

$m= nm_e$

Here,

m = Mass of the charge

n = Number of electrons

$m_e$ = Mass of the electron

$\text{Percentage change} = \frac{nm_e}{M}*100$

Replacing we have

$\text{Percentage change} = \frac{(2.5*10^13)(9.1*10^{-28})}{33}*100$

$\text{Percentage change} = 6.9*10^{-14} \%$

6 0

4 years ago

A 220 g mass is on a frictionless horizontal surface at the end of a spring that has force constant of 7.0

Talja [164]

The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:

x = 0.135 cm

Given parameters

The mass m = 220 g = 0.220 kg

The spring cosntnate3 k = 7.0 N / m

Initial displacement A = 5.2 cm = 5.2 10-2 m

To find

The position where the kinetic and potential energy are equal

A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.

x = A cos wt + fi

w² = $\frac{k}{m}$

Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.

The speed is defined by the variation of the position with respect to time.

v = $\frac{dx}{dt}$

let's evaluate

v = - A w sin (wt + Ф)

Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.

0 = - A w sin Ф

For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero

x = A cos wt

Let's find the point where the kinetic and potential energy are equal.

K = U

½ m v² = m g x

we substitute

½ A² w² sin² wt = g A cos wt

sin² wt = $\frac{2g}{A}$ cos wt

let's calculate

w = $\sqrt{\frac{7}{0.220} }$

w = 5.64 rad / s

sin² 5.64t = 2 9.8 / 0.052 cos 5.64t

sin² 5.64t = 376.92 cos 5.64 t

1 - cos² 5.64t = 376.92 cos 5.64t

cos² 5.64t -376.92 cos564t -1 = 0

we make the change of variable

x = cos 5.64t

x²- 376.92 x - 1 = 0

x = 0.026

cos 5.64t = 0.026

Let's find the displacement for this time

x = 5.2 10-2 0.026

x = 1.35 10-3 m

In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:

x = 0.135 cm

Learn more here: brainly.com/question/15707891

8 0

3 years ago

A long hollow cylindrical conductor (inner radius = 2.0 mm, outer radius = 4.0 mm) carries a current of 12 a distributed uniform

11Alexandr11 [23.1K]

Here we can use ampere'a law to find the magnetic field

$\int B.dl = \mu_o i_{en}$