Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
The answer is B . Brønsted-Lowry Acid/bases trade H+
When light travels from air into water,it slows down,causing it to change directions slightly
Answer:
carbon
Explanation:
because it is an allotrope of carbon
Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. This is because the bond distance in methyl bromide is more due to the large size of bromine atom.
Dipole moment is calculated by multiplying the charge on the atom with the bond distance.
