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kow [346]
3 years ago
15

| f − 6 | = | f + 8 |

Mathematics
1 answer:
ikadub [295]3 years ago
8 0

Answer:

f = - 1

Step-by-step explanation:

f - 6 = f + 8

f - 6 = - (f + 8)

f ∈ ∅

f - 6 = - (f + 8)

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If a car is traveling at 70 mph, how fast is the car traveling in feet per second? Round to 2 decimal places. (Reminder: there a
alukav5142 [94]

Answer:

264000

Step-by-step explanation:

5 0
3 years ago
Write an equation for the line perpendicular to the line y= -2/3+7 which passes through the point (-5,6)
zysi [14]
Y = -2/3x + 7.....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. All tht means is take the original slope, flip it, and change the sign. So we take -2/3....flip it making it -3/2.....change the sign making it 3/2. So ur perpendicular line will have a slope of 3/2.

y = mx + b
slope(m) = 3/2
(-5,6)....x = -5 and y = 6
now sub and find b, the y int
6 = 3/2(-5) + b
6 = -15/2 + b
6 + 15/2 = b
12/2 + 15/2 = b
27/2 = b
so ur perpendicular equation is : y = 3/2x + 27/2 <==
8 0
3 years ago
Can someone pls make me a factor tree of 995- Lower factors go first
Daniel [21]

Answer:

5 x 199

Step-by-step explanation:

You can see that it is divisible by 5, a prime number, because it ends in 5. Once you divide it, you get 199 which itself is a prime number.

3 0
3 years ago
Read 2 more answers
18% of the the students at a school are in year 8 and 16% of the students are in year 9. If the school has 126 tera 8 students,
yarga [219]

Answer:

112

Step-by-step explanation:

The general form of all percentage questions is: the chunk= (some percentage) (of the whole), or c=p*w

We know that 18% of students are 8th grade and that is 126 students, so p = 0.18 and c=126 (126 students are 18% of the whole school)

126 = (0.18)w, divide both sides by 0.18

126/(0.18) = w = 700

9th graders are 16% of the school or 16% of 700 students

c = (0.16) 700 = 112 students

5 0
3 years ago
Sophia ate 5.6 ounces less trail mix than Charlotte.
Bess [88]
The answer is 3/4 hope i help
4 0
3 years ago
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