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Lapatulllka [165]
2 years ago
15

Two students performed the same experiment separately and each one of them recorded two readings of mass which are given below.

Correct reading of mass is 3.0 g. On the basis of given data, mark the correct option out of the following statements. Student Readings (i) (ii) A 3.01 2.99 B 3.05 2.95 (i) Results of both the students are neither accurate nor precise. (ii) Results of student A are both precise and accurate. (iii) Results of student B are neither precise nor accurate. (iv) Results of student B are both precise and accurate.
answer it clearly ​
Chemistry
2 answers:
enyata [817]2 years ago
6 0

Answer:

The answer is option ii ,hope it helps

Lapatulllka [165]2 years ago
5 0

Answer:

Hey weirdo what's up?

So you got a question huh?

Lemme answer

As said the correct reading is 3.0grams

And the option A has 3.01 and 2.99 which are very mush precise and accurate to 3.0 gram don't you think?

So the answer is

Option ii the result of students A is both precise and accurate

Loye ya

Peace out

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3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
Morgarella [4.7K]

Answer:

Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

Thus, the total number of molecules turns out:

Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec

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