I believe that the answer is A. Decaying
Al₂O has a higher percentage of aluminium.
Explanation:
To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:
Molar mass of Al₂O = 2(27) + 16 = 70g/mol
Molar mass of Al(NO₃)₃ = 27 + 3[14 + 3(16)] = 213g/mol
Percentage by mass of Al in Al₂O =
x 100 = 77%
Percentage by mass of Al in Al(NO₃)₃ =
x 100 = 12.7%
Al₂O has a higher percentage of aluminium.
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Explanation:
A Bronsted-Lowry base is a substance that accepts a proton in the form of a hydrogen (H) atom.
On the other hand;
Bronsted-Lowry acid is the substance that donates the proton.
HF (aq) + SO32- ⇌ F- + HSO3-
In the forward reaction;
Bronsted-Lowry acid : HF
Bronsted-Lowry base: SO32-
In the backward reaction;
Bronsted-Lowry acid : HSO3-
Bronsted-Lowry base: F-
The conjugate base of HF is F-
The conjugate acid of SO32- is HSO3-
Answer:
Rate = k . [B]² . [C]
Explanation:
The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.
![Rate=k.[A]^{x} .[B]^{y} .[C]^{z}](https://tex.z-dn.net/?f=Rate%3Dk.%5BA%5D%5E%7Bx%7D%20.%5BB%5D%5E%7By%7D%20.%5BC%5D%5E%7Bz%7D)
where,
k is the rate constant
x, y, z are the reaction orders.
- <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
- <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
- The rate of the reaction is linearly dependent on the concentration of C. This means that the reaction order for C is z = 1, that is, a linear dependence.
All in all, the rate equation is:
Rate = k . [B]² . [C]
Answer:
Solutions are always homogeneous.
Explanation:
Solution:
Solution are considered homogeneous because in solution the ratio of solute and solvent remain the same throughout the solution. Both solute and solvent are chemically combined and form a new substance.
In solution the particles of solute can not be seen through naked eye.
When the light is passed through the solution it can not scattered.
Example:
When salt is dissolve in water it makes a solution.
The solution also exist in gaseous form. For example oxygen and many other gases dissolved in nitrogen also form a solution.
Mixture:
In mixture substance are physically combined. In mixture every every individual particle retain their properties.
It can be consist of solid, liquid and gas.
Examples:
Sand in water is also a mixture.
Oil in water form mixture.