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3 years ago

A car covers 400m distance in 50 sec find it's speed?

Physics

1 answer:

Lena [83]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf 8 \ m/s}}$

Explanation:

Speed is equal to distance over time.

$s=\frac{d}{t}$

The distance is 400 meters and the time is 50 seconds.

$d= 400 \ m \\t= 50 \ s$

Substitute the values into the formula.

$s=\frac { 400 \ m }{ 50 \ s}$

Divide.

$s= 8 \ m/s$

The speed of the car is 8 meters per second.

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3 years ago

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2 years ago

2. A 20 cm object is placed 10cm in front of a convex lens of focal length 5cm. Calculate

adoni [48]

Answer:

 » Image distance :

${ \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\$

v is image distance
u is object distance, u is 10 cm
f is focal length, f is 5 cm

${ \tt{ \frac{1}{v} + \frac{1}{10} = \frac{1}{5} }} \\ \\ { \tt{ \frac{1}{v} = \frac{1}{10} }} \\ \\ { \tt{v = 10}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: image \: distance \: is \: 10 \: cm \: \: }}}}}$

 » Magnification :

• Let's derive this formula from the lens formula:

${ \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\$

» Multiply throughout by fv

${ \tt{fv( \frac{1}{v} + \frac{1}{u} ) = fv( \frac{1}{f} )}} \\ \\ { \tt{ \frac{fv}{v} + \frac{fv}{u} = \frac{fv}{f} }} \\ \\ { \tt{f + f( \frac{v}{u} ) = v}}$