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RSB [31]
3 years ago
5

QUESTION 7

Chemistry
1 answer:
Temka [501]3 years ago
5 0

The student's test average is : 0.92

Total score obtained = 369

Number of tests = 4

Since Each test is exactly 100 points ;

The total score obtainable is (100 × 4) = 400

Average = score obtained / total score obtainable

Average = 369 / 400

Average = 0.9225

Average = 0.92

Learn more : brainly.com/question/9416487?referrer=searchResults

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When is friction advantageous and when is it not advantageous? Explain.
Novosadov [1.4K]

Answer:

here

Explanation:

FRICTION ADVANTAGES:

a) the soles of are shoes are designed in a way that they create friction and prevent us from slipping and falling.

b) We are capable of writing with a pen due to the friction between the pen and the paper.

FRICTION DISADVANTAGES:

b) Forest fires are caused due to the friction between the trees branches

( please vote me for brainliest )

5 0
4 years ago
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Gennadij [26K]
C. Wavelength will increase
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3 years ago
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
You water three sunflower plants with salt water. Each plant receives a different concentration of salt solutions. A fourth plan
quester [9]

Answer:

Please please please mark me brainlest!

Explanation:

IV: salt solution

DV: Hight of plants

Control: the fourth plant

Independent Variable: what it's watered with (regular water or salt water as well as the concentration of salt water)

Dependent Variable: Height

Control: the type of plant (sunflower) Hope this helps you! Ask me anything if you have any quistions!

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