An athlete preparing for a marathon runs 21.3 miles. How many kilometers did they run?
1 answer:
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Number of moles = 8.3 x 10⁻¹³
<h3>Further explanation </h3>The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
5 x 10¹¹ atoms of Silver :
Answer:
102g
Explanation:
To find the mass of ethanol formed, we first need to ensure that we have a balanced chemical equation. A balanced chemical equation is where the number of atoms of each element is the same on both sides of the equation (reactants and products). This is useful as only when a chemical equation is balanced, we can understand the relationship of the amount (moles) of reactant and products, or to put it simply, their relationship with one another.
In this case, the given equation is already balanced.
From the equation, the amount of ethanol produced is twice the amount of yeast present, or the same amount of carbon dioxide produced. Do note that amount refers to the number of moles here.
Mole= Mass ÷Mr
Mass= Mole ×Mr
<u>Method 1: using the </u><u>mass of glucose</u>
Mr of glucose
= 6(12) +12(1) +6(16)
= 180
Moles of glucose reacted
= 200 ÷180
= mol
Amount of ethanol formed: moles of glucose reacted= 2: 1
Amount of ethanol
=
= mol
Mass of ethanol
=
=
= 102 g (3 s.f.)
<u>Method 2: using </u><u>mass of carbon dioxide</u><u> produced</u>
Mole of carbon dioxide produced
= 97.7 ÷[12 +2(16)]
= 97.7 ÷44
= mol
Moles of ethanol: moles of carbon dioxide= 1: 1
Moles of ethanol formed= mol
Mass of ethanol formed
=
= 102 g (3 s.f.)
Thus, 102 g of ethanol are formed.
Additional:
For a similar question on mass and mole ratio, do check out the following!
Answer : The volume of carbon dioxide will be, 5.6122 L
Solution : Given,
Moles of LiOH = 0.5 moles
Molar mass of carbon dioxide = 44 g/mole
Density of carbon dioxide = 0.00196 g/ml
First we have to calculate the mass of carbon dioxide.
The balanced reaction will be,
From the reaction we conclude that
As, 2 moles of LiOH absorbs 44 grams of carbon dioxide
So, 0.5 moles of LiOH absorbs grams of carbon dioxide
Mass of carbon dioxide = 11 g
Density of carbon dioxide = 0.00196 g/ml
Now we have to calculate the volume of carbon dioxide.
Volume of carbon dioxide = 5612.24 ml = 5.6122 L (1 L = 1000 ml)
Therefore, the volume of carbon dioxide will be, 5.6122 L