All categories

3 years ago

Thermoplastics can be made to act more like thermosets by a process called cross-linking

Chemistry

2 answers:

kakasveta [241]3 years ago

7 0

True :))))))))))))))))))))

Darina [25.2K]3 years ago

5 0

It is True 100%.

Good luck :)

You might be interested in

at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were

Nataly [62]

Answer: The percent change in volume will be 25 %

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1$

Putting values in above equation, we get:

$\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L$

Percent change of volume = $\frac{\text{Change in volume}}{\text{Initial volume}}\times 100$

Percent change of volume = $\frac{(2-1.5)}{2}\times 100=25\%$

Hence, the percent change in volume will be 25 %

5 0

2 years ago

A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?

Leno4ka [110]

Answer : The volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K$

Putting values in above equation, we get:

$\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L$

Therefore, the volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

3 0

3 years ago

Dipole-dipole interactions are (weaker than, stronger than, equal to) hydrogen bonds.

kozerog [31]

Answer and Explanation:

Dipole-Dipole interactions are weaker than hydrogen bonds.

Hydrogen bonds are a form of dipole-dipole interactions, being the strongest form of dipole-dipole interactions.

#teamtrees #PAW (Plant And Water)

7 0

2 years ago

KMnO4 Assign oxidation numbers to each element in this compound.

zysi [14]

K=+1

Mn= +7

O= -2

That’s it!!!

8 0

3 years ago

PLEASE HELP ASAP! AND PLEASE DO NOT GIVE ME ANY VIRUSES!

sertanlavr [38]

Answer:

The first one and the last one.

Explanation:

Carbon dioxide is generated by cellular respiration and released into the atmosphere.

Photosynthesis makes oxygen that plants can release into the atmosphere.

8 0

2 years ago