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Snowcat [4.5K]
3 years ago
10

Please help me with this

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0
The smaller angle = 58
the larger angle = 122
reply to me in comments if you want the proof
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Solve:<br><br> a.x3+x2-8x - 12x+2<br> b. x3-4x2-3x + 18x-3<br> c. x2 + 4x + 4<br> d. x2 - 6x + 9
NeTakaya
<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}

Now you can rewrite it as:

(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}

Next, multiply:

(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}

Next, divide:

(\frac{f}{g})(x)=(x+2)^2

And lastly, simplify:

  • A good tip: (x+y)^2=x^2+2xy+y^2

(\frac{f}{g})(x)=x^2+4x+4

<h2>Answer:</h2>

<u>The correct option is C. x² + 4x + 4.</u>

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