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2 years ago

15

There are three subatomic particles found inside atoms. Two of the subatomic particle have a charge of positive or negative. The

one particle that does NOT have a charge is the:
proton

neutron

electron

none of the above

2 answers:

maksim [4K]2 years ago

8 0

Neutrons. they don’t have a charge

NARA [144]2 years ago

7 0

Neutrons don't have a charge. They are neutral

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2 drops of vinegar & 2 drops ammonia solution or not

Naya [18.7K]

Answer:

No, this is false because we know about the law that says if you add two things together you are adding the masses together, 2 drops of vinegar and 2 drops of ammonia would equal four drops of solution not two

Hope this helps!!

Explanation:

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2 years ago

A chemical reaction produces 3.81g potassium chloride (KCl). How many formula units of potassium chloride are there? *Find Molar

Aleks04 [339]

Answer:

The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²

Explanation:

The given parameters is as follows;

The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g

The required information = The number of formula units of potassium chloride (KCl)

The Molar Mass of KCl = 74.5513 g/mol

$The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The \ mass \ of \ the substance}{The \ Molar \ Mass \ of \ the \ substance}$

Therefore, we have;

$The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles$

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units

Therefore;

0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units

From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.

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2 years ago

How does the Bohr's model of the atom differ from the quantum mechanical model?

Tom [10]

Bohr model is valid only for hydrogen and hydrogen-like species, but quantum mechanical model can explain all elements....

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2 years ago

Valence electrons are important because these are the only electrons involved with an atom's

Salsk061 [2.6K]

<span>Valence electrons are important because these are the only electrons involved with an atom's chemical reactivity.</span>

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3 years ago

Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of

lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

$U_{2}-U_{1}=Q-W$

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

$dw=Pdv$

The pressure is constant, so: $w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg}$ (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

$U_{2}-U_{1}=500-(3*75)=275kJ$

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

$P_{1}V_{1}=nRT_{1}$

$P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}$

Subtracting the first from the second:

$1.5P_{1}V_{1}=nR(T_{2}-T_{1})$

Isolating $T_{2}$ :

$T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}$

Assuming that it is water steam, n=0.1666 kmol

$V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}$

$T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76$ ºC

7 0

2 years ago