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ehidna [41]
2 years ago
9

I need help with answering this please

Mathematics
2 answers:
Alex777 [14]2 years ago
5 0

Answer:

The awnser is C

Step-by-step explanation:

Because you have to divode and subtracted the next equation

love history [14]2 years ago
3 0
Ccccccccccccccccccccccccc
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Someone please help!!! Can’t find this one anywhere!!! please and thank you!!!!!!!
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subtract k^2 -15 from each side

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(k+7)(k-4)=0

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3 years ago
One third plus four sixths plus six eighteenths equals blank
ss7ja [257]

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1 1/3

Step-by-step explanation:

7 0
2 years ago
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Evaluate the expression for the given value of the variable.
MatroZZZ [7]

Answer:

17

Step-by-step explanation:

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The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [600]
\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
2 years ago
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