Answer:
Step-by-step explanation:
So this is our question
therefore we need to reduce the number of students for the food to be equivalent for 100 days so,
40 days → 150students
<h3> 100 days → </h3>
3 1/2 = 4/2 - 2/3
2×3 =6
12/6 -4/6 =8/6 =4/3 = 1 & 1/3
Plugging in the values y = 6 and when z = 3 into the given algebraic expression ³/₂y - 3 + ⁵/₃z gives us; 11
<h3>How to evaluate simple algebra?</h3>
We are given the algebraic expression;
³/₂y - 3 + ⁵/₃z
Now we want to solve this when y = 6 and when z = 3
Thus, we will plug in the values as y = 6 and when z = 3 into the given algebraic expression to get;
³/₂(6) - 3 + ⁵/₃(3) = 6 + 5
= 11
Thus, from the calculations above plugging in the values y = 6 and when z = 3 into the given algebraic expression ³/₂y - 3 + ⁵/₃z gives us; 11
Read more about Simple Algebra at; brainly.com/question/4541471
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