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3 years ago

Explain why it is not possible to determine the type of Atom by simplifying knowing how many neutrons it has.

Chemistry

2 answers:

nata0808 [166]3 years ago

7 0

Answer:

An atoms identity is defined by it's number of protons.

Explanation:

Neutrons do not define the identity of an atom, protons do. An element is defined by it's atomic number, Z, which is also the number of protons in an atom of that element.

alexdok [17]3 years ago

3 0

Answer:

It is not possible to accurately identify an element given only the number of neutrons. All atoms are made of three particles: electrons, protons and neutrons. The number of electrons is equal to the number of protons if the atom is uncharged.

Explanation:

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A sample of nitrogen occupies a volume of 250 mL at 25 oC. What volume will it occupy at 95 oC?

Volgvan

Answer:

308.7 mL

Explanation:

V1/T1 =V2/T2 T must be in K units

V2 = V1T2/T1

= (.250)(95 + 273.15) / (25 + 273.15) = .3087 LITER

4 0

3 years ago

Why can't you use pen to mark the chromatography paper in this experiment?

trasher [3.6K]

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4 years ago

PLEASE ANSWER

irga5000 [103]

Answer:

Explanation:

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3 years ago

What mass of hcl is consumed by the reaction of 5.0 moles of mg??

lianna [129]

The answer is c I think

5 0

3 years ago

A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound

Karolina [17]

Answer:

The empirical formula of the compound is $C_{0.504}HO_{1.008}$ .

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen ( $H$ ) is scaled up to a mole, since it has the molar mass, and both carbon ( $C$ ) and oxygen ( $O$ ) are also scaled up in the same magnitude. The empirical formula is of the form:

$C_{x}HO_{y}$

Where $x$ , $y$ are the number of moles of the carbon and oxygen, respectively.

The scale factor ( $r$ ), no unit, is calculated by the following formula:

$r = \frac{M_{H}}{m_{H}}$ (1)

Where:

$m_{H}$ - Mass of hydrogen, in grams.

$M_{H}$ - Molar mass of hydrogen, in grams per mole.

If we know that $M_{H} = 1.008\,\frac{g}{mol}$ and $m_{H} = 0.2\,g$ , then the scale factor is:

$r = \frac{1.008}{0.2}$

$r = 5.04$

The molar masses of carbon ( $M_{C}$ ) and oxygen ( $M_{O}$ ) are $12.011\,\frac{g}{mol}$ and $15.999\,\frac{g}{mol}$ , then, the respective numbers of moles are: ( $r = 5.04$ , $m_{C} = 1.2\,g$ , $m_{O} = 3.2\,g$ )