Answer:
1.04 moles of AlCl₃
Explanation:
Balanced Equation: 2Al°(s) + 3Cl₂(g) => 2AlCl₃(s)
Approach => convert given data (28 g Al°) to moles. The number of moles AlCl₃ would equal the number of moles aluminum because coefficients for Aluminum and Aluminum Chloride are equal.
moles Al° = (28g)/(27g/mole ) = 1.04 mole Al°
From balanced equation moles AlCl₃ produced equals moles of Al° produced = 1.04 mole AlCl₃ because coefficients of Al° & AlCl₃.
Answer:
Mass = 0.6 g
Explanation:
Given data:
Moles of NaOH = 0.015 mol
Mass of NaOH = ?
Solution:
Number of moles = mass/ molar mass
by rearranging this formula,
Mass = number of moles × molar mass
Molar mass of NaOH is 40 g/mol
by putting values,
Mass = 0.015 mol × 40 g/mol
Mass = 0.6 g
Answer:
Gallium - Phosphorous - Fluorine - Chlorine
Explanation:
