A solution has a pOH of 7. 1 at 10∘c. Then the pH of the solution given that kw=2. 93×10−15 at this temperature is 7.4 .
It is given that,
pOH of solution = 7.1
Kw =2.93×10^(-15)
Firstly, we will calculate the value of pKw
The expression which we used to calculate the pKw is,
pKw=-log [Kw]
Now by putting the value of Kw in this expression,
pKw =−log{2.93×10^(-15)}
pKw =15log(2.93)
pKw=14.5
Now we have to calculate the pH of the solution.
As we know that,
pH+pOH=pKw
Now put all the given values in this formula,
pH+7.1=14.5
pH=7.4
Therefore, we find the value of pH of the solution is, 7.4.
learn more about pH value:
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Answer:
1.586x10^-9
Explanation:
To make a multiplication in scientific notation we need to multiply the coefficients and sum the exponents:
Coefficients: 2.600 * 6.1000 = 15.86
Exponents: -5 + (-5) = -10
The result is:
15.86x10^-10
As the scientific notation must be given with only 1 number in the left of the point:
<h3>1.586x10^-9</h3>
The number of protons in the nucleus of the atom, I believe. c:
335K would be expressed as 61.85 degrees Celsius
