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Vesna [10]
3 years ago
7

You drop a stone down a well that is 100.0 m deep. How long will it take for the stone to reach the bottom, ignoring air resista

nce?
Remember, rest is the initial velocity and it equals 0.0 m/s
01.05
O 4.5 s
o 20 s
O 10 s
Physics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

4.5s

Explanation:

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A 1,000 kg ball traveling at 5 m/s would have
jonny [76]

Answer:

15 because 5×5×5 is the same thing as 5×3 which equals to 15

6 0
2 years ago
Read 2 more answers
At take off a plane flies 100 km north before turning east to fly 200 km east. How far is its destination from where the plane t
andrew-mc [135]

First the plane turns 100 km North, and than 200 km East. Since both the directions are perpendicular to each other, therefore we can apply the Pythagoras theorem to calculate the distance between the destination and the point where plane took off


=100^{2}+200^{2}

D=223.60 km=224 km

Therefore, The destination is 224 km from where the plane took off


8 0
3 years ago
We have three identical metallic spheres A, B, C. Initially sphere A is charged with charge Q, while B and C are neutral. First,
larisa [96]

Answer:

The final charges of each sphere are:   q_A = 3/8 Q , q_B = 3/8 Q ,               q_C = 3/4 Q

Explanation:

This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.

Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point

                q_A = Q / 2

                q_B = Q / 2

Now sphere A touches sphere C, ending with half the charge

                q_A = ½ (Q / 2) = ¼ Q

                q_B = ¼ Q

Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge

                  q = Q / 4 + Q / 2 = ¾ Q

This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q

                  q_A = 3/8 Q

                  q_B = 3/8 Q

The final charges of each sphere are:

                q_A = 3/8 Q

                q_B = 3/8 Q

                q_C = 3/4 Q

7 0
3 years ago
A person wearing a shoulder harness can survive a car crash if the acceleration is smaller than -300 m/s . assuming constant acc
mars1129 [50]

To solve this problem, we use the equation:

<span>d = (v^2  - v0^2) / 2a</span>

 

where,

d = distance of collapse

v0 = initial velocity = 101 km / h = 28.06 m / s

v = final velocity = 0

a = acceleration = - 300 m / s^2

 

d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)

<span>d = 1.31 m</span>

3 0
2 years ago
Can any kind soul help me please​
Alex

Answer:

I) 420000J

ii)

Explanation:

(I) so you can use the formula for quantity of heat then substitute the values given

formula-Q=mc∆9

3 0
2 years ago
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