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Mila [183]
3 years ago
14

What effect does Earth’s spherical shape have on the amount of sunlight that reaches the equator?

Physics
2 answers:
Natasha_Volkova [10]3 years ago
6 0
Because the Earth<span> is a sphere, the surface gets much more intense </span>sunlight<span>, hence heat, at </span>the equator<span>than at the poles.</span>
TiliK225 [7]3 years ago
5 0
<h2>Answer with Explanation </h2>

The reason of this is because the shape of the Earth is spherical, this causes the Earth’s surface to get struck by the sun’s rays at different angles, creating different variants in temperatures on Earth. A perpendicular (90 degrees) angle to the Earth is formed when the equator receives intense sunlight directly as compared to the poles. At the poles, upto period of 24 hours.

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3 years ago
A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target
stiks02 [169]

Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

\theta=35^{\circ}

a.Let v_0 be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

v_x=v_0cos\theta=v_0cos35

v_y=v_0sin\theta=v_0sin35

x=v_0cos\theta\times t=v_0cos35\times t

t=\frac{30}{v_0cos35}

h=v_yt-\frac{1}{2}gt^2

Substitute the values

1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2

1.8=30tan35-\frac{6574.6}{v^2_0}

\frac{6574.6}{v^2_0}=21-1.8=19.2

v^2_0=\frac{6574.6}{19.2}

v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

t=\frac{30}{18.5cos35}

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

7 0
3 years ago
if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?
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Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

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R = resistance (given as 15 ohm)

substituting the above values into the formula

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V = 9 Volts

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