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4 years ago

What effect does Earth’s spherical shape have on the amount of sunlight that reaches the equator?

2 answers:

6 0

Because the Earth<span> is a sphere, the surface gets much more intense </span>sunlight<span>, hence heat, at </span>the equator<span>than at the poles.</span>

TiliK225 [7]4 years ago

5 0

<h2>Answer with Explanation </h2>

The reason of this is because the shape of the Earth is spherical, this causes the Earth’s surface to get struck by the sun’s rays at different angles, creating different variants in temperatures on Earth. A perpendicular (90 degrees) angle to the Earth is formed when the equator receives intense sunlight directly as compared to the poles. At the poles, upto period of 24 hours.

You might be interested in

physical changes occur when existing bonds break and new bonds form

Luba_88 [7]

<span>A physical change is any change that alters the form or appearance of a substance but does not change it into another substance
-Some of the physical properties may be altered, but the chemical composition stays the same
-Examples: Bending, Crushing, Cutting, Melting, Freezing, Boiling</span>

6 0

3 years ago

Could a mixture be made up of only elements and no compounds?

GaryK [48]

A mixture is made of (elements).

6 0

3 years ago

If during the submerged weighing procedure air bubbles were to adhere to the object, how would the experimental results be affec

Mazyrski [523]

Answer:

see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas

Explanation:

We will propose this exercise using Archimedes' principle, which establishes that the thrust on a body is equal to the volume of the desalted liquid.

B = ρ g V

The weight of a submerged body is the net force between the weight and the thrust

F_net = W - B

we can write the weight as a function of the density

ρ_body = m / V

m = ρ_body V

W = mg

W = ρ _body g V

we substitute

F_net= ( ρ_body - ρ _fluid) g V

In general this force is directed downwards, we can call this value the apparent weight of the body. This is the weight of the submerged body.

W_aparente = ( ρ_body - ρ _fluid) g V

If some air bubbles formed in this body, the net force of these bubbles is

F_net ’= #_bubbles ( ρ_fluido - ρ_air) g V’

this force is directed upwards

whereby the measured force is

F = W_aparente - F_air

As we can see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas

6 0

3 years ago

A rock is thrown vertically upward from the origin of a reference frame. The rock reaches the peak of its trajectory and then it

Tema [17]

Answer:

The acceleration of the rock is negative throughout the whole motion. (TRUE)

The acceleration of the rock is zero at the peak of the trajectory (FALSE)

The velocity of the rock is positive throughout the whole motion (FALSE)

The position of the rock is positive or zero throughout the whole motion (TRUE)

The velocity of the rock is positive throughout the whole motion (FALSE)

Explanation:

1)The acceleration of the rock is negative throughout the whole motion. (TRUE)

Using the upward direction as positive

Then, The acceleration of the rock is negative throughout the whole motion.

2)The acceleration of the rock is zero at the peak of the trajectory.(FALSE)

Only the velocity can be zero at the peak the trajectory, the acceleration is not zero

3)The velocity of the rock is positive throughout the whole motion (FALSE)

Using the upward direction as positive, The velocity of the rock is only positive when going in upward direction and vice versa

4)The position of the rock is positive or zero throughout the whole motion (TRUE)

When the rock get down it will have a zero position, then when it get to the peak it will have positive position

6 0

4 years ago

A block slides forward 4.73 m while being pulled back by a 39.7 N force at 142° from the direction of motion. How much work does

lubasha [3.4K]

Answer:

work done by the force, W = -147.97 J

Given:

displacement of the box, s = 4.73 m

angle between force and displacement, $\theta = 142^{\circ}$

Force, F = 39.7 N

Solution:

Work done by the force can be expressed as the dot product of Force, F and displacement 's' is given by:

W = Fscos $\theta$

W = 39.7 $\times 4.73\times cos142^{\circ}$

W = -147.97 J

where negative sign indicates that work is done on the block

6 0

4 years ago