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3 years ago

Two identical speakers are 3.50 m

Physics

1 answer:

DiKsa [7]3 years ago

6 0

Answer:

The difference in distance from the speakers is 5.2 - 3.5 = 1.7 m

The listener would be 1/2 wavelength out of phase with the speakers

1/2 y = 1.7 m where y is the wavelength

y = 3.4 m the required wavelength

f = v / y = 340 m/s / 3.4 m = 100 / sec lowest frequency

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When a particle of charge q moves with a velocity v⃗ in a magnetic field B⃗ , the particle is acted upon by a force F⃗ exerted b

melomori [17]

Answer:

$3.8\cdot 10^{-16}N$

Explanation:

For a charged particle moving perpendicularly to a magnetic field, the magnitude of the force exerted on the particle is:

$F=qvB$

where

q is the magnitude of the charge of the particle

v is the velocity of the particle

B is the magnetic field strength

In this problem, we have

$q=e=1.6\cdot 10^{-19}$ is the charge of the electron

$v=6.0\cdot 10^6 m/s$ is the velocity

$B=4.0\cdot 10^{-4}T$ is the magnetic field

Substituting into the formula, we find the force:

$F=(1.6\cdot 10^{-19} C)(6.0\cdot 10^6 m/s)(4.0\cdot 10^{-4}T)=3.8\cdot 10^{-16}N$

8 0

4 years ago

When the mass of the cylinder increased by a factor of 3, from 1.0 kg to 3.0 kg, what happened to the cylinder’s gravitational p

const2013 [10]

Answer: Fourth option. It increased by a factor of 3.

Solution:

m1=1.0 kg

Cylinder's gravitational potential energy: Ep=m*g*h

Ep1=(1.0 kg)*g*h

Ep1=g*h

m2=3.0 kg

Ep2=(3.0 kg)*g*h

Ep2=3*g*h

Replacing g*h by Ep1 in the equation above:

Ep2=3*Ep1

Then, the cylinder's gravitational potential energy increased by a factor of 3.

3 0

4 years ago

Read 2 more answers

An artificial satellite of mass 900kg Is launched at a speed of 11,000 m/s from its launching station. How much is the kinetic e

Marina CMI [18]

Answer:

KE = 54450 J

Explanation:

Data:

m = 900 kg
v = 11.000 m/s
KE = ?

Use the formula:

$\boxed{\bold{K_{E}=\frac{m*(v)^{2}}{2}}}$

Replace and solve:

$\boxed{\bold{K_{E}=\frac{900\ kg*(11.000\frac{m}{s})^{2}}{2}}}$

$\boxed{\bold{K_{E}=\frac{900\ kg*121\frac{m^{2}}{s^{2}}}{2}}}$

$\boxed{\bold{K_{E}=\frac{108900\ J}{2}}}$

$\boxed{\boxed{\bold{K_{E}=54450\ J}}}$

A kinetic energy of <u>54450 Newtons</u> is imparted to it.

Greetings.

6 0

3 years ago

Three small but dense objects are located in the x-y plane as shown in the figure. The objects have the following masses: mA = 3

satela [25.4K]

The x and the y coordinates of the center of the mass of this system will be 43.1 m and 3.12 m respectively.

<h3>What is the center of mass?</h3>

A location is established in relation to an object or set of objects in the center of mass. It is the system's average position across all of its components.

Given data;

There are three little objects that are densely spaced out in the x-y plane.;

The value of the masses

m₁=1.41 kg

m₂=2.55 kg

m₃=3.19 kg

$\rm X_{cm} =\frac{ (W_1x_1 + W_2x_2 + W_3x_3)}{(W_1 + W_2 + W_3)} \\\\\ X_{cm} ==\frac{1.41 \times 2 + 2.55 \times 6 +3.19 \times 4}{1.41+2.55+3.19} \\\\ X_{cm} =4.31 \ m$

$\rm Y_{cm} =\frac{ (W_1y_1 + W_2y_2 + W_3y_3)}{(W_1 + W_2 + W_3)} \\\\\ X_{cm} ==\frac{1.41 \times 2 + 2.55 \times 4 +3.19 \times 7}{1.41+2.55+3.19} \\\\ X_{cm} =3.12 \ m$

Hence, the x and the y coordinates of the center of the mass of this system will be 4.31 m and 3.12 m respectively.

To learn more about the center of mass, refer;

brainly.com/question/8662931

#SPJ1

3 0

2 years ago

Which of the following is true for all types of fronts (warm, cold , stationary, and occluded)?

Taya2010 [7]

Can't see any choices but isn't it something to do with different air masses "meeting" each other such as hot air and cold air, with maybe a spot of water vapour and a few winds thrown in for good stormy weather ?

3 0

3 years ago