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Bas_tet [7]
3 years ago
10

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5220km away, and released. It found its way

back to its nest a time 12.8days after release.a. If we place the origin in the nest and extend the +x-axis to the release point, what was the bird's average velocity for the return flight?v= ___.b. What was the bird's average velocity in m/s for the whole episode, from leaving the nest to returning?v= ___.
Physics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

-4.72005 m/s

0 m/s

Explanation:

Displacement = 5220 km

Time = 12.8 days

The average velocity is given by

v_a=\dfrac{0-5220\times 10^3}{12.8\times 24\times 60\times 60}\\\Rightarrow v_a=-4.72005\ m/s

The average  for the return flight is -4.72005 m/s

When the total displacement is divided by the total time of a journey then we get the average velocity.

Displacement is the minimum distance between the initial and final points of the journey.

Here, the displacement of the whole episode is 0 as the initial and final point is zero.

Hence, the average velocity for the whole episode is 0 m/s

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kozerog [31]

Answer:

43.7 °C

Explanation:

\alpha_b = Coefficient of linear expansion of brass = 18\times 10^{-6}\ ^{\circ}C

\alpha_s = Coefficient of linear expansion of steel = 11\times 10^{-6}\ ^{\circ}C

L_{0b} = Initial length of brass = 31 cm

L_{0s} = Initial length of steel = 11 m

\Delta L = Total change in length = 3 mm

Total change in length would be

\Delta L=\Delta L_b+\Delta L_s\\\Rightarrow \Delta L=L_{0b}\alpha_b\Delta T+L_{0s}\alpha_b\Delta T\\\Rightarrow \Delta T=\frac{\Delta L}{L_{0b}\alpha_b+L_{0s}\alpha_b}\\\Rightarrow \Delta T=\frac{0.003}{0.31\times 18\times 10^{-6}+11\times 10^{-6}\times 11}\\\Rightarrow \Delta T=23.7\ ^{\circ}C

\Delta T=23.7\\\Rightarrow T_f-T_i=23.7\\\Rightarrow T_f=23.7+T_i\\\Rightarrow T_f=23.7+20\\\Rightarrow T_f=43.7\ ^{\circ}C

The final temperature is 43.7 °C

6 0
3 years ago
A 25 N force stretches a spring 280 cm. What was the spring constant? ​
boyakko [2]

Answer:

  1. F= 25N
  2. ∆l=280cm
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4 0
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The gravitational force between two objects will be greatest in which of the following situations?
Kobotan [32]

Answer:

Explanation:

Gravitational law states that, the force of attraction or repulsion between two masses is directly proportional to the product of the two masses and inversely proportional to the square of their distance apart.

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Combining the two equation

F ∝ M1•M2 / R²

G is the constant of proportional and it is called gravitational constant

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So, option c is correct

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