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Bas_tet [7]
2 years ago
10

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5220km away, and released. It found its way

back to its nest a time 12.8days after release.a. If we place the origin in the nest and extend the +x-axis to the release point, what was the bird's average velocity for the return flight?v= ___.b. What was the bird's average velocity in m/s for the whole episode, from leaving the nest to returning?v= ___.
Physics
1 answer:
denis-greek [22]2 years ago
3 0

Answer:

-4.72005 m/s

0 m/s

Explanation:

Displacement = 5220 km

Time = 12.8 days

The average velocity is given by

v_a=\dfrac{0-5220\times 10^3}{12.8\times 24\times 60\times 60}\\\Rightarrow v_a=-4.72005\ m/s

The average  for the return flight is -4.72005 m/s

When the total displacement is divided by the total time of a journey then we get the average velocity.

Displacement is the minimum distance between the initial and final points of the journey.

Here, the displacement of the whole episode is 0 as the initial and final point is zero.

Hence, the average velocity for the whole episode is 0 m/s

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artcher [175]
Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

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8 0
3 years ago
A 200 kg chunck of lead falls from a hight of 30m and smashes into a rigid floor. calculate the increse in internal engery
mr Goodwill [35]

Answer:

\Delta E=58800\ J

Explanation:

Given:

mass of lead chunk, m=200\ kg

height of the fall, h= 30\ m

  • Assuming the collision to be perfectly inelastic the whole kinetic energy of the chunk is lost after the collision.
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So, increase in the internal energy of the system after the collision is :

\Delta E=m.g.h

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\Delta E=58800\ J

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8 0
2 years ago
The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting
faltersainse [42]

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GPE = 1200(1.6)(350) = 672000 J


Hope this answers the question. Have a nice day.

5 0
3 years ago
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