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AVprozaik [17]
2 years ago
10

7th grade science , please don’t get the answer from the internet :(

Chemistry
1 answer:
Liula [17]2 years ago
7 0

Answer:

See the answer below

Explanation:

1. Organisms produce energy for cells by chemically breaking down and unlocking the energy locked-up within food materials in a process known as cellular respiration. The unlocked energy is then utilized for the cell's metabolic activities.

2. Cellular respiration can be aerobic or anaerobic.

Aerobic respiration involves the breakdown of carbohydrates in the presence of oxygen to yield energy in the form of ATP while carbon dioxide and water are produced as by-products.

        C_6H_1_2O_6 + 6O_2 --> 6CO_2 + 6H_2O + ATP

Anaerobic respiration involves the breakdown of carbohydrates in the absence of oxygen to produce ATP and lactic acid as a by-product. The lactic acid is later oxidized to carbon dioxide and water to prevent it from building up.

       C_6H_1_2O_6 -> 2C_3H_6O_3 + ATP

3. Photosynthesis and cellular respiration are both considered metabolic processes that take place in living organisms. However, photosynthesis is peculiar only to green plants and some algae while respiration is common to all living organisms. While photosynthesis is anabolic, that is, it involves the building up of materials; respiration is said to be catabolic because it involves the breaking down of materials.

During photosynthesis, inorganic products are utilized to produce carbohydrates for plants with oxygen gas released as a by-product according to the following equation:

       6CO_2 + 6H_2O --> C_6H_1_2O_6 + 6O_2

During respiration, the food taken by living organisms is broken down to unlock the energy in it for metabolic activities according to the following equation:

     C_6H_1_2O_6 + 6O_2 --> 6CO_2 + 6H_2O + ATP

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Answer:

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3 years ago
in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,
insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, H_{supplied} = 3.34 × 10³ J

The amount thermal energy gained by the kettle, H_{absorbed}  = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}}  \times 100

Therefore, we get;

\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3}  \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%

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4 0
2 years ago
What sequence of enzymes allows for the synthesis of glycogen from glucose-6-phosphate?
Nutka1998 [239]

Answer:

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UDP-glucose pyrophosphorylase:  Form UDP-glucose from glucose-1-phosphate.

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Answer:

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The extra expansion and flattening with result in the loss of intermolecular forces and won’t remain as a solid and form other states of matter which won’t be able to cover the surface.

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